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4 years ago

A group of organs that perform a body function is called a

2 answers:

8 0

The answer would be Organ system.
Organs group together usually to perform a function in the body.

Ex.) Kinda like the digestive system, the stomach, large and small intestines you get the idea. In the digestive system many organs work together to be able to digest food.

xz_007 [3.2K]4 years ago

3 0

Cell
Tissue
Organ
ORGAN SYSTEM
organism
community
population
ecosystem
biosphere

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In an emergency an airplane needs to land on a short runway at Albany County Airport. The plane comes in for a landing with a sp

zvonat [6]

Answer:

t = 13.43 s

Explanation:

In order to find the minimum time required by the plane to stop, we will use the first equation of motion. The first equation of motion is written as follows:

Vf = Vi + at

where,

Vf = Final Velocity of the Plane = 0 m/s (Since, the plane finally stops)

Vi = Initial Velocity of the Plane = 95 m/s

a = deceleration of the plane = - 7.07 m/s²

t = minimum time interval needed to stop the plane = ?

Therefore,

0 m/s = 95 m/s + (- 7.07 m/s²)t

t = (95 m/s)/(7.07 m/s²)

6 0

3 years ago

Un adolescente que va en monopatín rueda hacia abajo sobre un plano inclinado de 18.0 m de largo. El chico parte con una rapidez

qaws [65]

Answer: 31.62°

Explanation:

Tenemos como datos:

Distancia = 18.0m

Velocidad inicial = 2.0 m/s

Tiempo total = 3.3s

Sabemos que para un plano inclinado (ignorando el rozamiento) la aceleración se escribe como:

a(t) = g*sen(θ)

donde θ es el ángulo del plano inclinado, y g = 9.8m/s^2

Sabemos que para la velocidad tenemos que integrar la aceleración sobre el tiempo, entonces:

v(t) = g*sen(θ)*t + v0

Donde v0 es la velocidad inicial: v0 = 2.0m/s

v(t) = 9.8m/s^2*sen(θ)*t + 2.0m/s

Y para la posición, podemos integrar de vuelta sobre el tiempo:

p(t) = 0.5*9.8m/s^2*sen(θ)*t^2 + 2.0m/s*t + p0

Donde p0 es la posición inicial, podemos considerar que es cero para este problema.

p(t) = 4.9m/s^2*sen(θ)*t^2 + 2.0m/s*t

Y usando los datos iniciales, sabemos que en 3.3 segundos se recorren 18 metros, entonces:

p(3.3s) = 18m = 4.9m/s^2*sen(θ)*(3.3s)^2 + 2.0m/s*3.3s

18m = 51.744m*sen(θ) + 6.6m

sen(θ) = (18m - 6.6m)/ 51.744m

θ = cosec( (18m - 6.6m)/ 51.744m ) = 31.62°

4 0

3 years ago

A baby was born on his due date, but doctors determined that a valve in his heart was too short to adequately pump blood to his

Ivanshal [37]

Answer:

He had a cogenital condition

Explanation:

cogenital conditions are present before or at the time of birth and are considered birth defects

3 0

3 years ago

Complete the sentences below correctly. Stunt Car A and Stunt Car B are identical cars with the same mass of 48.9 kg. They are b

ivann1987 [24]

Answer:

Stunt Car A experiences a large force over a short period of time. Stunt Car B experiences a small force over a long period of time. Because of the force experienced by Stunt Car A, it will sustain more damage than Stunt Car B.

Explanation:

Both cars have the same mass and velocity, therefore they have the same momentum. During the collision, the total momentum of the car A and brick wall is conserved as well as the total momentum of the car B and the pile of leaves.

However, if we are to investigate the damage on each car, we should look at the cars not the whole system. So, the momentum difference between the cars gives us the impulse that the car felt.

$\vec{J} = \Delta \vec{P}\\\vec{F}\Delta t = \vec{P}_2 - \vec{P}_1$