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Kamila [148]
3 years ago
11

Helpppp nowwww plsss!!

Chemistry
1 answer:
pogonyaev3 years ago
5 0

Answer:

A

Explanation:

if the earth slows down then that will give more time to the sun meaning days/nights will be longer

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The ratio of the moisture content in the air compared to the maximum amount of moisture that the air can hold at its current tem
PSYCHO15rus [73]
<h2>Relative Humidity</h2>

Explanation:

  • Humidity is the amount of moisture content present in the atmosphere.

    Humidity is of two types:

  1. Absolute humidity.
  2. Relative humidity.
  • Absolute humidity is the ratio of  the amount of moisture content in the air to the unit volume of the air.
  • Relative humidity can be derived as the ratio of moisture content in the air to the maximum amount of moisture that the air constitutes.
  • Hence, the required answer is Relative humidity.
6 0
4 years ago
How many molecules are in 9.40 moles of AICI3?
Aleks04 [339]
The answer would 5.66 x 10 power of 24
8 0
3 years ago
For the reaction at 298 K, 2NO2(g) N2O4(g) the values of ΔH° and ΔS° are -58.03 kJ and -176.6 J/K, respectively. Calculate the v
Ierofanga [76]

Answer:

\Delta G^o=-5.4032 kJ

The temperature for \Delta G^o=0[/tex is [tex]T=328.6 K

Explanation:

The three thermodinamic properties (enthalpy, entropy and Gibbs's energy) are linked in the following formula:

\Delta G^o=\Delta H^o + T*\Delta S^o

Where:

\Delta G^o is Gibbs's energy in kJ

\Delta H^o is the enthalpy in kJ

\Delta S^o is the entropy in kJ/K

T is the temperature in K

Solving:

\Delta G^o=-58.03 kJ - 298K*-0.1766 kJ/K

\Delta G^o=-5.4032 kJ

For \Delta G^o=0:

0=\Delta H^o - T*\Delta S^o

\Delta H^o= T*\Delta S^o

T=\frac{\Delta H^o}{\Delta S^o}

T=\frac{-58.03 kJ}{-0.1766 kJ/K}

T=328.6 K

3 0
3 years ago
Read 2 more answers
HELP!!!
WARRIOR [948]

Answer:

no

Explanation:

4 0
3 years ago
Yeast and other organisms can convert glucose (C6H12O6) to ethanol (CH3CH2OH) by a process called alchoholic fermentation. The n
NISA [10]

Answer:

8.37 grams

Explanation:

The balanced chemical equation is:

C₆H₁₂O₆     ⇒   2 C₂H₅OH (l) + 2 CO₂ (g)

Now we are asked to calculate the mass  of glucose required to produce 2.25 L CO₂ at 1atm and 295 K.

From the ideal gas law we can determine the number of moles that the 2.25 L represent.

From there we will use the stoichiometry of the reaction to determine the moles of glucose which knowing the molar mass can be converted to mass.

PV = nRT    ⇒ n = PV/RT

n= 1 atm x 2.25 L / ( 0.08205 Latm/kmol x 295 K ) =0.093 mol CO₂

Moles glucose required:

0.093 mol CO₂  x  ( 1 mol C₆H₁₂O₆   / 2 mol CO₂ ) =  0.046 mol C₆H₁₂O₆

The molar mass of glucose is 180.16 g/mol, then the mass required is

0.046 mol x 180.16 g/mol = 8.37 g

5 0
3 years ago
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