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olya-2409 [2.1K]
3 years ago
5

What is the coldest temperature ever achieved?

Chemistry
2 answers:
Georgia [21]3 years ago
8 0
For the whole world, the lowest temperature on earth was recorded at -128.6 degrees in Russia. This was in July of 1983
kupik [55]3 years ago
5 0

Answer:

The lowest natural temperature ever directly recorded at ground level on Earth is −89.2 °C

-273.144 degrees celsius. This is close to 'absolute zero', which is equal to -273.15 degrees celsius

Explanation:

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When bromine water is shaken with a liquid organic compound it is rapidly
dybincka [34]

answer:

This allows us to tell alkenes apart from alkanes using a simple chemical test. Bromine water is an orange solution of bromine. It becomes colourless when it is shaken with an alkene. Alkenes can decolourise bromine water, but alkanes cannot.

explanation:

5 0
2 years ago
Why does a metal spoon left on a bowl of hot soup become warm?
irakobra [83]

Answer:

A) Metal is a conductor.

7 0
3 years ago
Three-year-old Ben and his father are playing with a ball at the park. Ben's father throws a
GenaCL600 [577]

Answer:

His dad knows about gravity and, unless gravity was not working, anything with mass will be pulled back to earth

Explanation:

:)

8 0
3 years ago
Read 2 more answers
How many cubic centimeters of an ore containing only 0.22% gold (by mass) must be processed to obtain $100.00 worth of gold? The
bezimeni [28]

Answer:

The cubic centimetres of the ore containing 0.22% gold (by mass) that must be processed to obtain the $100.00 worth of gold is approximately 216 cm³

Explanation:

The percentage by mass of gold in the ore = 0.22%

The density of the ore = 8.0 g/cm³

The price of the gold = $818 per troy ounce

14.6 troy oz = 1.0 pound

1 lb = 454 g

Given that one troy ounce = $818

$100 worth of gold = 1/818 ×100 troy ounce = 100/818 troy ounce

1 troy oz = 1.0/14.6 lb

100/818 troy oz =  100/818 × 1.0/14.6 lb = 250/29857 lb ≈ 0.0084 lb

1 lb = 454 g

250/29857 lb = 454 × 250/29857 g ≈ 3.8015 g

$100 = 3.8015 g worth of gold

The mass, M, of the ore containing 3.8015 g of gold is given as follows;

0.22% of M = 3.8015 g

0.22/100 × M = 3.8015 g

M = 3.8015 g × 100/0.22 = 1727.933 g

The volume, V, of the ore containing 3.8015 g of gold is given as follows;

Density of ore = Mass of ore/(Volume of ore)

Volume of ore = Mass of ore /(Density of ore)

The density of the ore = 8.0 g/cm³

Volume of ore = 1727.933 g /(8.0 g/cm³) = 215.99 cm³ ≈ 216 cm³

Therefore, the cubic centimetres of the ore containing 0.22% gold (by mass) that must be processed to obtain the $100.00 worth of gold ≈ 216 cm³.

5 0
3 years ago
Given the formula for an organic compound:
Dmitriy789 [7]
Based on the picture,
The name given to the group in the box would be : Ethyl

You can see that in the picture it has 2 carbon side chains, which mean it categorized as Ethyl

hope this helps
3 0
3 years ago
Read 2 more answers
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