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2 years ago

Which one of the following elements will combine with chlorine in a 12 ratio to give a formula of XCI2.?

Chemistry

2 answers:

Svetradugi [14.3K]2 years ago

6 0

Answer:

Explanation:

marusya05 [52]2 years ago

3 0

Answer:

the answer is magnesium

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A closed loop through which current can flow is called a(n): ____________.

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3 years ago

The chemical equation below shows the photosynthesis reaction. 6co2 6h2o right arrow. c6h12o6 6o2 the molar mass of carbon dioxi

iogann1982 [59]

The moles of water are used in the given reaction between CO₂ & H₂O is 12 moles.

<h3>How do we calculate mass from moles?</h3>

Mass of any substance will be calculated by using their moles as:

n = W/M , where

W = given or required mass

M = molar mass

Given chemical reaction is:

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

Moles of 528 g of CO₂ = 528g / 44.01g/mol = 11.99 moles

From the stoichiometry of the reaction, it is clear that:

6 moles of CO₂ = reacts with 6 moles of H₂O

So, 11.99 moles of CO₂ = reacts with 11.99 = 12 moles of H₂O

Hence option (a)is correct i.e. 12 moles.

To know more about moles, visit the below link:

brainly.com/question/15373263

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2 years ago

Question 11: How does the energy of a photon emitted when the electron moves from the 3rd orbital to the 2nd orbital compare to

hodyreva [135]

Answer:

Explanation:

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3 years ago

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3 years ago

Read 2 more answers

How many atoms are in 5 grams of H2O?

mojhsa [17]

Hello!

We know that by the Law of Avogrado, for each mole of substance we have 6.02 * 10²³ atoms, if:

The molar mass of water (H2O)

H = 2 * (1u) = 2u

O = 1 * (16u) = 16u

---------------------------

The molar mass of H2O = 2 + 16 = 18 g / mol

If:

1 mol we have 6.02 * 10²³ atoms

1 mole of H2O we have 18 g

Then we have:

18 g ------------- 6.02 * 10²³ atoms

5 g -------------- x

$\dfrac{18}{5} = \dfrac{6.02*10^{23}}{x}$

$18*x = 5*6.02*10^{23}$

$18\:x = 3.01*10^{24}$

$x = \dfrac{3.01*10^{24}}{18}$

$\boxed{\boxed{x \approx 1.672*10^{23}\:atoms}}\end{array}}\qquad\checkmark$

I Hope this helps, greetings ... DexteR! =)

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3 years ago

Read 2 more answers