To justify the yearly membership, you want to pay at least the same amount as a no-membership purchase, otherwise you would be losing money by purchasing a yearly membership. So set the no-membership cost equal to the yearly membership cost and solve.
no-membership costs $2 per day for swimming and $5 per day for aerobic, in other words, $7 per day. So if we let d = number of days, our cost can be calculated by "7d"
a yearly membership costs $200 plus $3 per day, or in other words, "200 + 3d"
Set them equal to each other and solve:
7d = 200 + 3d
4d = 200
d = 50
So you would need to attend the classes for at least 50 days to justify a yearly membership. I hope that helps!
Answer:
y=-1
Step-by-step explanation:
it is a straight line graph with no gradient therefore no X value. It crosses the y axis at -1
Given equation : n(17+x)=34x−r.
We need to solve it for x.
Distributing n over (17+x) on left side, we get
17n + nx = 34x - r.
Adding r on both sides, we get
17n+r + nx = 34x - r+r.
17n + r + nx = 34x.
Subtracting nx from both sides, we get
17n + r + nx-nx = 34x-nx
17n + r = 34x -nx.
Factoring out gcf x on right side, we get
17x + r = x(34-n).
Dividing both sides by (34-n), we get
<h3>Therefore, final answer is
</h3>
Answer:
Based off of the calculations I did, I got 32 as the answer.
Step-by-step explanation:
Jason uses 10/6 of the paint for each chair he paints and according to the question, there are 19 chairs.
So we multiply these two numbers to get the amount of paint used after painting all 19 chairs.
10/6 * 19 = 31.666...
Then we add the previous amount Jason used for painting the furniture to the total amount of paint used after painting the 19 chairs.
31.666... + 4/12 = 32.
Thus, Jason used 32 cans of paint in total.
Answer:
Step-by-step explanation:
The point-slope form of an equation of a line:
<em>(x₁, y₁)</em><em> - point on a line</em>
<em>m</em><em> - slope</em>
<em />
We have
Substitute:
Convert to the standard form
<em> use the distributive property</em>
<em>add 5 to both sides</em>
<em>add 4x to both sides</em>
