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Kryger [21]
3 years ago
11

johnny has 5 chocolate bars, jimmy being the bully eats 4 of the bars johnny had. How many do johnny have left??

Mathematics
1 answer:
Fiesta28 [93]3 years ago
3 0

Answer:

1

Step-by-step explanation:

5-4 = 1

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Justine had 88 dolphin stickers. She gave 4 stickers each to 6 friends. How many stickers does Justine have left?
MatroZZZ [7]

Answer:64

Step-by-step explanation:

4×6=24

88-24=64

3 0
3 years ago
A recipe for chicken marinade says, "Mix 3 parts oil with 2 parts soy sauce and 1 part orange juice." If you need 42 cups of mar
iVinArrow [24]

Answer:

We will use;

21 parts oil

14 parts soy sauce

7 parts Orange

Step-by-step explanation:

We can have all of these as a ratio

That would be;

3 + 2 + 1 = 6

For oil

3/6 * 42 = 21 parts of oil

For Soy sauce

= 2/6 * 42 = 14 parts soy sauce

For Orange

= 1/6 * 42 = 7 parts orange juice

5 0
3 years ago
Read 2 more answers
A researcher gathers a sample of n=89 people to try a new
muminat

Answer:

24

Step-by-step explanation:

+#;$;_;_:;+$hshshsbbsns

5 0
3 years ago
Jeremy wants to determine the number of solutions for the equation below without actually solving the equation.
Degger [83]

Answer:

  1 solution

Step-by-step explanation:

Jeremy can simplify the equation enough to determine if the x-coefficient on one side of the equation is the same or different from the x-coefficient on the other side. Here, that simplification is ...

  -3x -3 +3x = -3x +3 +3

We see that the x-coefficient on the left is 0; on the right, it is -3. These values are different, so there is one solution.

__

In the attached, the left-side expression is called y1; the right-side expression is called y2. The two expressions are equal where the lines they represent intersect. That point of intersection is x=3. (For that value of x, both sides of the equation have a value of -3.)

__

<em>Additional comment</em>

If the equation's x-coefficients were the same, we'd have to look at the constants. If they're the same, there are an infinite number of solutions. If they are different, there are no solutions.

8 0
3 years ago
Read 2 more answers
Show do i solve for the missing answers
BARSIC [14]
(g + f)(x)
g(x) + f(x)
x - 1 + x^2 + 4
x^2 + x + 3

(g - h)(x)
g(x) - h(x)
3x + 1 - (2x - 2)
3x + 1 - 2x + 2
x + 3
5 0
2 years ago
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