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weeeeeb [17]
2 years ago
12

Dividing radicals Simplify

Mathematics
1 answer:
Luden [163]2 years ago
3 0

Answer:

\frac{\sqrt{17} (-3-\sqrt{2})}{51}

You might be interested in
What is the solution of StartRoot x minus 4 EndRoot + 5 = 2?
Vlad1618 [11]

Answer:

13

Step-by-step explanation:

\sqrt{x-4}+5=2 \\\\\sqrt{x-4}=-3 \\\\x-4=9 \\\\x=13

Hope this helps!

6 0
3 years ago
Read 2 more answers
Combine 2y+1x=40 and y=2x using substitution
fomenos

2(2x) + 1x = 40 or 4x + 1x = 40 is the result of combining by substitution

<em><u>Solution:</u></em>

Given that we have to combine 2y + 1x = 40 and y = 2x using substitution method

The substitution method for solving systems of equations involves expressing one variable in terms of another, thus removing one variable from an equation.

<em><u>Given equations are:</u></em>

2y + 1x = 40 -------- eqn 1

y = 2x ----------- eqn 2

We can substitute eqn 2 in eqn 1

Which means, substitute y = 2x in place of y in eqn 1

2(2x) + 1x = 40

4x + 1x = 40

5x = 40

x = 8

From eqn 2,

y = 2(8)

y = 16

Thus by combining using substitution method we found the solution

3 0
3 years ago
Let $a$ and $b$ be nonzero real numbers such that
algol [13]
<h3>Answer:   -7/2</h3>

=========================================================

Explanation:

Let's expand out (2 - 7i)(a + bi) using the FOIL rule

(2 - 7i)(a + bi) = 2a + 2bi - 7ai - 7bi^2

(2 - 7i)(a + bi) = 2a + 2bi - 7ai - 7b(-1)

(2 - 7i)(a + bi) = 2a + 2bi - 7ai + 7b

(2 - 7i)(a + bi) = (2a+7b) + (2bi-7ai)

(2 - 7i)(a + bi) = (2a+7b) + (2b-7a)i

We're told the result is purely imaginary. What this means is that the real part (2a+7b) is zero, while the imaginary part (2b-7a) is nonzero. If both are zero, then we have 0+0i = 0 which is purely real.

For example, the complex numbers 0-7i and 0+2i are purely imaginary.

Let's use the fact that 2a+7b must be zero to do the following steps:

2a+7b = 0

2a = -7b

a = -7b/2

a/b = -7/2 which is the final answer

We must check to see if 2b-7a is nonzero

2b - 7a = 2b - 7(-7b/2)

2b - 7a = 2b + 24.5b

2b - 7a = 26.5b

The result is nonzero if and only if b is nonzero. Luckily we're told b is nonzero at the top of the problem. So we don't have any worries that (2b-7a) is zero.

Therefore, (2a+7b) + (2b-7a)i will be purely imaginary with a/b = -7/2

------------------

A concrete example:

Let a = -14 and b = 4

a/b = -14/4 = -7/2

(2-7i)(a+bi) = (2-7i)(-14+4i) = 0 + 106i which is purely imaginary.

I'll let you do the steps in expanding that out using the FOIL rule.

4 0
1 year ago
Cathy drank 600 mL of water at school and another 400 mL at home. How many liters of water did Cathy drink?
liraira [26]
Cathy drank 1,000 ml of water which means she drank 1 liter.
8 0
2 years ago
Two ballpoint pens are selected at random from a box that contains 3 blue pens, 2 red pens, and 3 green pens. If X is the number
Flauer [41]

Answer:

a) f(x,y) =\frac{\binom{3}{x}\binom{2}{y}\binom{3}{2-x-y}}{\binom{8}{2}} ;   x = 0, 1 , 2;  y = 0, 1 , 2; 0 ≤ x+y ≥ 2

b) = \frac{9}{14}

Step-by-step explanation:

joint probability is a function that characterizes the distribution of a random variable. If X and Y be two random variables then the joint probability will be P(X = x, Y=y)

Given Data,

X = The number of blue Pens

Y = The number of red Pens

a)

possible outcomes(X, Y) are (0, 0), (0, 1), (1, 0), (1, 1), (0, 2), (2,0)

Please refer fig. also

total number ways of selecting any 2 pens = \binom{8}{2}= \frac{8!}{2! 6!} =28

f(x,y) = \frac{\binom{3}{x}\binom{2}{y}\binom{3}{2-x-y}}{\binom{8}{2}} ;   x = 0, 1 , 2;  y = 0, 1 , 2; 0 ≤ x+y ≥ 2

b)

P(X,Y)∈A = P(X + Y ≤ 1)

= P(0,0) + P(1,0) + P(0,1)

= \frac{3}{28} + \frac{3}{14} + \frac{9}{28}

= \frac{9}{14}

4 0
3 years ago
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