Ask question

Ask question

All categories

Svetradugi [14.3K]

3 years ago

10

The pie chart shows information about pupils in KS3 at a school Altogether, there are 200 pupils in ks3 a) How many pupils are i

n year7? b) how many pupils are in year 9

1 answer:

Charra [1.4K]3 years ago

6 0

Answer:

a) 75

b)25

Step-by-step explanation:

You might be interested in

A factory can produce 60 TVs in 7 days. How long does it take to finish 400 TVs?<br>

andreev551 [17]

Answer:

57.12, but being precise and accurate, you might wanna put 58.

Step-by-step explanation:

So, there's this guy, his name is calculator.

3 0

4 years ago

Find the distance<br> (-6, -5) and (2, 0)

tiny-mole [99]

Hey there! I'm happy to help!

To find the distance between two points, you find the difference between the x values, square that, find the difference between the y values, square that, add the two numbers you got, and then find the square root.

Find the difference between the x values.

-6-2=-8

Square it.

-8²=64

Find the difference between the y-values.

-5-0=-5

Square it.

-5²=25

We add the two numbers we got.

64+25=89

And we find the square root.

√89≈9.43

This method comes from the Pythagorean Theorem! If you draw a triangle that connects the two points, you can use the Pythagorean Theorem to find the distance, which is what we just did!

Have a wonderful day! :D

3 0

4 years ago

Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. Illustra

Rainbow [258]

Answer:

$x = t$

$y = 1 - t$

$z = 2t$

Step-by-step explanation:

Given

$x=t$

$y=e^{-t}$

$z=2t-t^2$

(0, 1, 0)

The vector equation is given as:

$r(t) = (x,y,z)$

Substitute values for x, y and z

$r(t) = (t,\ e^{-t},\ 2t - t^2)$

Differentiate:

$r'(t) = (1,\ -e^{-t},\ 2 - 2t)$

The parametric value that corresponds to (0, 1, 0) is:

$t = 0$

Substitute 0 for t in r'(t)

$r'(t) = (1,\ -e^{-t},\ 2 - 2t)$

$r'(0) = (1,\ -e^{-0},\ 2 - 2*0)$

$r'(0) = (1,\ -1,\ 2 - 0)$

$r'(0) = (1,\ -1,\ 2)$

The tangent line passes through (0, 1, 0) and the tangent line is parallel to r'(0)

It should be noted that:

The equation of a line through position vector a and parallel to vector v is given as:

$r(t) = a + tv$

Such that:

$a = (0,1,0)$ and $v = r'(0) = (1,-1,2)$

The equation becomes:

$r(t) = (0,1,0) + t(1,-1,2)$

$r(t) = (0,1,0) + (t,-t,2t)$

$r(t) = (0+t,1-t,0+2t)$

$r(t) = (t,1-t,2t)$

By comparison:

$r(t) = (x,y,z)$ and $r(t) = (t,1-t,2t)$

The parametric equations for the tangent line are:

$x = t$

$y = 1 - t$

$z = 2t$

7 0

3 years ago

Need Help With This

podryga [215]

Answer:

4n-13

Step-by-step explanation:

Terms= -13 (constant)

Coefficient= 3, -5, 6

Like term= 3n, -5n, 6n

3n-13-5n+6n

3n+6n-5n-13

9n-5n-13

4n-13

Hope this helps ;) ❤❤❤

4 0

3 years ago

In one u.s. City the taxi cost is $2 plus $ .50 per mile. If you are traveling from the airport, there is an additional charge o

Nana76 [90]

35 miles from the ariport subtracting 6 dollars for the initial fee and the tolls

6 0

3 years ago