Given this reaction: 4K(s) + O2(g)→2K2O(s). Calculate how many grams of product is produced if 2.50 g of each reactant is reacte
1 answer:
Answer:
Explanation:
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In this case, since 2.50 g of both potassium (molar mass = 39.1 g/mol) and gaseous oxygen (molar mass = 32.0 g/mol) react in a 4:1 and 1:2 mole ratio respectively, to produce potassium oxide (molar mass = 94.2 g/mol), we evaluate the mass of potassium oxide yielded by each reactant in order to identify the limiting one via stoichiometry:
Thus, since the 2.50 g of potassium yields 3.01 g of potassium oxide, we infer it is the limiting reactant and that is the mass of produced product by the reaction.
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The molarity of a Sodium carbonate solution : 0.373 M
<h3>Further explanation</h3>Given
32.52 g Na₂CO₃
822 ml of solution = 0.822 L
Required
The molarity
Solution
Molarity shows the number of moles of solute in every 1 liter of solution.
mol of solute = mol of Na₂CO₃ :
= mass : MW Na₂CO₃
= 32.52 g : 106 g/mol
= 0.307
Molarity :
= n : V
= 0.307 mol : 0.822 L
= 0.373 M