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nordsb [41]
3 years ago
5

At high pressures how does the volume of a real gas compare with the volume of an ideal gas under the same conditions and why

Chemistry
2 answers:
malfutka [58]3 years ago
3 0
Answer: No, a<span>t high pressures, volume of a real gas does not  compare with the volume of an ideal gas under the same conditions.

Reason: 
For an ideal gas, there should not be any intermolecular forces of interaction. However, for real gases there are intermolecular forces of interaction like dipole-dipole and dipole-induced dipole. Further, at high pressures, molecules are close by. Hence, extend of these intermolecular forces is expected to be high. This results in decreases in volume of real gas. Thus, </span>volume of a real gas does not  compare with the volume of an ideal gas under the same conditions.

Lyrx [107]3 years ago
3 0

Answer:

At high pressure, volume of a real gas is lower than volume of an ideal gas under the same condition

Explanation:

At high pressure, total volume of gas molecules are no longer negligible as compared to volume of gas or more precisely volume of gas container.

For ideal gases, gas molecules are assumed to be point masses. That means, ideal gas molecules do not have measurable volumes.

But, in real gases, gas molecules have small but measurable volume.

At low pressure, volume a gas is so high that volume of gas molecules are neglected. Hence real gases behaves ideally at low pressure.

But, at high pressure, actual volume of a gas should be volume of gas container minus volume of gas molecules.

hence volume of a real gas is lower than ideal gas at high pressure

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If water were a non-polar<br> Molecule
JulijaS [17]

Answer:

Water would not be able to transport nutrients -‐-‐ in plants, or in our bodies -‐-‐ nor to dissolve and transport waste products out of our bodies. ... Cohesiveness, adhesiveness, and surface tension: would decrease because without the +/-‐ polarity, water would not form hydrogen bonds between H20 molecules.

8 0
2 years ago
1. For each of the molecules below, determine the electron geometry, molecule geometry, and bond
Alexxx [7]

Answer:

CCl4- tetrahedral bond angle 109°

PF3 - trigonal pyramidal bond angles less than 109°

OF2- Bent with bond angle much less than 109°

I3 - linear with bond angles = 180°

A molecule with two double bonds and no lone pairs - linear molecule with bond angle =180°

Explanation:

Valence shell electron-pair repulsion theory (VSEPR theory) helps us to predict the molecular shape, including bond angles around a central atom, of a molecule by examination of the number of bonds and lone electron pairs in its Lewis structure. The VSEPR model assumes that electron pairs in the valence shell of a central atom will adopt an arrangement which tends to minimize repulsions between these electron pairs by maximizing the distance between them. The electrons in the valence shell of a central atom are either bonding pairs of electrons, located primarily between bonded atoms, or lone pairs. The electrostatic repulsion of these electrons is reduced when the various regions of high electron density assume positions as far apart from each other as possible.

Lone pairs and multiple bonds are known to cause more repulsion than single bonds and bond pairs. Hence the presence of lone pairs or multiple bonds tend to distort the molecular geometry geometry away from that predicted on the basis of VSEPR theory. For instance CCl4 is tetrahedral with no lone pair and four regions of electron density around the central atom. This is the expected geometry. However OF2 also has four regions of electron density but has a bent structure. The molecule has four regions of electron density but two of them are lone pairs causing more repulsion. Hence the observed bond angle is less than 109°.

8 0
3 years ago
To which planet do scientist compare to Kepler-10
Stells [14]
To Earth, since it has the same radio and masses. This is what I believe.
7 0
3 years ago
12.<br> An object with a mass of 3 kg has a momentum of 75 kg•m/s. What is the velocity?
marissa [1.9K]

Answer:

the velocity is 25 m/s

Explanation:

The computation of the velocity is shown below:

As we know that

Magnitude of Momentum = (mass) × (speed)

75 kg. m/s = 3 kg × speed

So, the speed is

= 75 ÷ 3

= 25 m/s

hence, the velocity is 25 m/s

3 0
2 years ago
• 1) The pressure of a sample of gas in a 2.00-L container is 876 mmHg.
kifflom [539]

Answer:

4380 mmHg

Explanation:

Boyle's Law can be used to explain the relationship between pressure and volume of an ideal gas. The pressure is inversely related to volume, so if volume decrease the pressure will increase. It can be expressed in the equation as:

P1V1=P2V2

In this question, the first condition is 2L volume and 876 mmHg pressure. Then the system changed into the second condition where the volume is 400ml and the pressure is unknown. The pressure will be:

P1V1= P2V2

876 mmHg * 2L = P2 * 400ml /(1000ml/L)

P2= 876 mmHg * 2L / 0.4L

P2= 4380 mmHg

5 0
3 years ago
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