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nordsb [41]
3 years ago
5

At high pressures how does the volume of a real gas compare with the volume of an ideal gas under the same conditions and why

Chemistry
2 answers:
malfutka [58]3 years ago
3 0
Answer: No, a<span>t high pressures, volume of a real gas does not  compare with the volume of an ideal gas under the same conditions.

Reason: 
For an ideal gas, there should not be any intermolecular forces of interaction. However, for real gases there are intermolecular forces of interaction like dipole-dipole and dipole-induced dipole. Further, at high pressures, molecules are close by. Hence, extend of these intermolecular forces is expected to be high. This results in decreases in volume of real gas. Thus, </span>volume of a real gas does not  compare with the volume of an ideal gas under the same conditions.

Lyrx [107]3 years ago
3 0

Answer:

At high pressure, volume of a real gas is lower than volume of an ideal gas under the same condition

Explanation:

At high pressure, total volume of gas molecules are no longer negligible as compared to volume of gas or more precisely volume of gas container.

For ideal gases, gas molecules are assumed to be point masses. That means, ideal gas molecules do not have measurable volumes.

But, in real gases, gas molecules have small but measurable volume.

At low pressure, volume a gas is so high that volume of gas molecules are neglected. Hence real gases behaves ideally at low pressure.

But, at high pressure, actual volume of a gas should be volume of gas container minus volume of gas molecules.

hence volume of a real gas is lower than ideal gas at high pressure

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3 years ago
In the reaction of 675.9 grams of barium chloride and excess silver(I) nitrate, how many grams of silver(I) chloride should get
zvonat [6]

Taking into account the reaction stoichiometry, the mass of silver(I) chloride formed is 930.37 grams.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 AgNO₃ + BaCl₂ → 2 AgCl + Ba(NO₃)₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • AgNO₃: 2 moles
  • BaCl₂: 1 mole
  • AgCl: 2 moles
  • Ba(NO₃)₂: 1 mole

The molar mass of the compounds is:

  • AgNO₃: 169.87 g/mole
  • BaCl₂: 208.24 g/mole
  • AgCl: 143.32 g/mole
  • Ba(NO₃)₂: 261.34 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

AgNO₃: 2 moles ×169.87 g/mole= 339.74 grams

BaCl₂: 1 mole ×208.24 g/mole= 208.24 grams

AgCl: 2 moles ×143.32 g/mole= 286.64 grams

Ba(NO₃)₂: 1 mole×261.34 g/mole= 261.34 grams

<h3>Mass of silver(I) chloride formed</h3>

The following rule of three can be applied:  if by reaction stoichiometry 208.24 grams of barium chloride form 286.64 grams of silver(I) chloride, 675.9 grams of barium chloride form how much mass of silver(I) chloride?

mass of silver(I) chloride=\frac{675.9 grams of barium chloride x286.64 grams of silver(I) chloride }{208.24 grams of barium chloride}

mass of silver(I) chloride= 930.37 grams

Finally, the mass of silver(I) chloride formed is 930.37 grams.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

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