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zhannawk [14.2K]
2 years ago
6

A man ran the 200m race within 19.19 seconds. Calculate the speed of the man during the race

Physics
1 answer:
natta225 [31]2 years ago
4 0

Answer:

around 23 miles per hour

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List 5 reason why water is not thermometric liquid​
kolezko [41]

Answer:

(1) it is transparent so it makes the reading difficult. (2) it is volatile. (3) it is a poor conductor of heat. (4) it has a higher specific heat capacity, so it absorbs more heat from the body with which it is kept in contact. (5) Water cannot be used in thermometer because of its higher freezing point and lower boiling point than other liquids . If water is used in a thermometer , it will start phase change at 0oC and 100oC and will not measure temperature , out of this range .

PLEASE READ CAREFULLY AND PLEASE MARK AS BRAINLIEST :)

5 0
3 years ago
A small spinning asteroid is in a circular orbit around a star, much like the earth's motion around our sun. The asteroid has a
Fudgin [204]

Answer:

Temperature will be 305 K  

Explanation:

We have given The asteroid has a surface area A=7.70m^2

Power absorbed P = 3800 watt

Boltzmann constant \sigma =5.67\times 10^{-8}Wm/K^4

According to Boltzmann rule power radiated is given by

P=\sigma AT^4

3800=5.67\times 10^{-8}\times 7.70\times T^4

T^4=87.0381\times 10^8

T=305K

So temperature will be 305 K  

8 0
3 years ago
Numatoms is initially 7. what is numatoms after: numatoms += 5?
Neporo4naja [7]
S s. S s abbs s sbsbs z sbs
8 0
2 years ago
In February 1955, a paratrooper fell 365 m from an airplane without being able to open his chute but happened to land in snow, s
DaniilM [7]

Answer:

a. i=4760 kg*m/s

b. D_U= 1.11 m

Explanation:

a)

F= 120,000N

Kinetic energy @ impact = 120,000*depth

K_E= (1/2)*85kg*(56m/s)^2

K_E=133280 J

D_U= \frac{133280J}{120000N} = 1.11 m

b)

The momentum is equal to the impulse on him from the snow so:

p=m*v

p=85kg*56m/s

i=4760 kg*m/s

7 0
3 years ago
8. Il An 8.00 kg package in a mail-sorting room slides 2.00 m down a
Vitek1552 [10]

Answer:

See below

Explanation:

Normal force = m g cos 53 = 8 kg * 9.8 m/s^2 * cos 53 = 47.1823 N

  no work is done by this force

Force friction = coeff friction * force normal = .4 * 47.1823 = 7.55 N

   work of friction = 7.55 * 2 m = 15.1 j

Force Downplane = mg sin 53 = 62.61  N

    work = 62.61 * 2 = 125.22 j

Net Force downplane =   force downplane - force friction = 55.06 N

net Work = force * distance = 55.06 N * 2 M = 110.12 j

3 0
2 years ago
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