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zubka84 [21]
4 years ago
13

Suppose a treadmill has an average acceleration of .0050 m/s2. How much does it's speed changer after 4.8 minutes?

Physics
1 answer:
avanturin [10]4 years ago
3 0
This one is nice and straight forward :)

simply calculate how many seconds are in 4.8 minutes like this:
4.8min x 60s = 288s

Then to find the ∆v (∆v = symbol for change in velocity) multiply the acceleration 0.0050m/s^2 by 288s
∆v = 1.44m/s



0.0050m/sx^{2}




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3 0
4 years ago
a Porsche 911 accelerates from rest to 27 metre per second due north in 5.8 seconds the mass of the car is 1400 kg what is the m
user100 [1]

Answer:

The average force has a magnitude 6524 N due north.

Explanation:

The average net force F = ma where m = mass of car = 1400 kg and a = acceleration.

a = (v - u)/t where u = initial velocity of car = 0 m/s (since it starts from rest)

v = final velocity of car = 27 m/s due north and t = time of motion = 5.8 s

a = (27 m/s - 0 m/s)/5.8 s = 27 m/s ÷ 5.8 s = 4.66 m/s

Since the direction of the velocity change is the direction of the acceleration, the acceleration is 4.66 m/s due north.

The average force, F = ma = 1400 kg × 4.66 m/s = 6524 N

Since the acceleration is due north, the average force takes the direction of the acceleration.

So the direction of the average force is due north

The average force has a magnitude 6524 N due north.

7 0
3 years ago
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