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horrorfan [7]
3 years ago
13

Is speed or velocity more helpful to a pilot?

Physics
2 answers:
ladessa [460]3 years ago
8 0
<span>From experience it is far more important to know where you are going (direction) than how fast you are going (magnitude), though both are ...</span>
Dima020 [189]3 years ago
3 0
Velocity, as it is is a vector quantity, so it has both direction and magnitude.
Speed is a scalar quantity, so it only has magnitude, no direction.
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Choose 3 ways to keep our bodies healthy
Alina [70]

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take daily showers . eat vegies .sanitize your hands

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2 years ago
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Analyze how some insects are able to move around on the surface of a lake or pond
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3 years ago
(PLEASE HELP) Identify the following as electromagnetic (E) or mechanical (M) waves.
fomenos
Sound waves (m)

water waves (m)

radio waves (e)

ultraviolet (e)

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3 0
3 years ago
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if you throw a rock straight up at a speed of 19m/s. How long goes it take the ball to reach its maximum height?
Scrat [10]

Answer:

It requires <u>1.9 seconds</u> to reach maximum height.

Explanation:

As per given question,  

Initial velocity (U) =19 m/s

Final velocity (V) = 0 m/s

\text { Taking acceleration due to gravity }(a)=10 \mathrm{m} / \mathrm{s}^{2}

Maximum height = S

Time taken is "t"

<u>Calculating time taken to reach maximum height:</u>

We know that time taken to reach the maximum height is calculated by using the formula V = U + at

Substitute the given values in the above equation.

Final velocity is “0” as there is no velocity at the maximum height.

0=19+10 \times t

-19=10 \times t

\frac{-19}{10}=t

t = 1.9 seconds.

The time taken to reach maximum height is <u>1.9</u> seconds.

<u>Calculating maximum height</u>:

\text { Consider the equation } V^{2}-U^{2}=2 a S

Solving the equation we will get the value of S

0-19^{2}=2 \times(-10) \times \mathrm{S} .(-\text { is due to opposite of gravity) }

-361 = -20S

Negative sign cancel both the sides.

\mathrm{S}=\frac{361}{20}

S = 18.05 m

Maximum height is 18.05 m  .

3 0
3 years ago
if a 5-kg bowling ball is projected upward witha velocity of 2.0 m/s, then what is the recoil velocity of the Earth(mass=6.0×10^
vitfil [10]

by the concept of momentum conservation we can say

if net force on a system of mass is ZERO then its momentum will remain conserved

Here a ball is projected upwards so if we take Ball + Earth as a system then total momentum of the system will remain conserved

Initially when ball is on the surface of earth the system has zero momentum and hence we can say after throwing the ball momentum of earth + ball must be zero

now using same equation we can say

P_{ball} + P_{earth} = 0

m_1v_1 + m_2v_2= 0

given that

m_1 = 5 kg

v_1 = 2 m/s

m_2 = 6 * 10^{24} kg

from above equation velocity of earth will be

v_2 = \frac{m_1 v_1}{m_2}

v_2 = \frac{5*2}{6 * 10^{24}}

v_2 = 1.67 * 10^{-24} m/s

so above will be the recoil speed of earth

3 0
3 years ago
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