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pantera1 [17]
2 years ago
7

A car of mass 1200 kg, moving with a speed of 72 mph on a highway,

Physics
1 answer:
Keith_Richards [23]2 years ago
8 0

momentum(p) = mass(m) x velocity(v)

KE = kinetic energy = 1/2 mv²

a.

the ratio of the momentum of the SUV to that of the car

\tt \dfrac{mv}{1.5m\dfrac{2}{3}v }=1:1

b.  the ratio of the KE of the SUV to that of the car

\tt \dfrac{1/2\times mv^2}{1/2\times 1.5m\times (\dfrac{2}{3}v )^2}=\dfrac{mv^2}{1.5m\dfrac{4}{6}v^2 }=1:1

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Answer:

Explanation:

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t₁ = \frac{t}{\sqrt{1-\frac{v^2}{c^2} } }

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C ) Given t = 10 years , t₁ = ? v = .8c

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D ) Given t = 10 years , t₁ = ? v = .4c

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=1.09 x 10

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