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4 years ago

In a cell, the amount nutrition coming in equals the amount of waste going out. This is an example of _____.

Physics

1 answer:

babymother [125]4 years ago

5 0

The answer is B) equilibrium
hope this helps!=-)

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Identify one factors that has caused some spcies to become extinct

Sunny_sXe [5.5K]

Well one of the factors is that the species is poorly adapted to the their environment and die off

3 0

4 years ago

Where does the heat come from that creates the motion for continental drift?

poizon [28]

Answer:

The heat doesn't come from any of those the heat comes from the Sun

Explanation:

But the thing that holds the heat from the Sun is the Earth's atmosphere.

When he gets hot the carbon dioxide holds in the heat but when the when oxygen it meets the heat in the air it makes it become cooler

4 0

3 years ago

(i) Two 110V lamps are connected in parallel. Their ratings are 150W and 200W.

LekaFEV [45]

Answer:

37.7 Ω

Explanation:

The resistance in each lamp is:

P = IV = V²/R

R = V²/P

R₁ = (110 V)² / (150 W)

R₁ = 80.67 Ω

R₂ = (110 V)² / (200 W)

R₂ = 60.5 Ω

Their combined resistance in parallel is:

1/R = 1/R₁ + 1/R₂

1/R = 1/(80.67 Ω) + 1/(60.5 Ω)

R = 34.57 Ω

So the current that goes through them is:

V = IR

I = V/R

I = (110 V) / (34.57 Ω)

I = 3.182 A

We need the same current in the new circuit.

V = IR

230 V = (3.182 A) (R₃ + 34.57 Ω)

R₃ = 37.7 Ω

We can check our answer by finding the voltage drop across this resistor:

V = I R₃

V = (3.182 A) (37.7 Ω)

V = 120 V

230 V − 120 V = 110 V, the correct voltage for the lamps.

7 0

3 years ago

A horizontal force of 40N is needed to pull a 60kg box across the horizontal floor at which coefficient of friction between floo

Mazyrski [523]

Answer:

Coefficient of friction is $0.068$ .

Work done is $320~J$ .

Explanation:

Given:

Mass of the box ( $m$ ): $60$ kg

Force needed ( $F$ ): $40$ N

The formula to calculate the coefficient of friction between the floor and the box is given by

$F=\mu mg...................(1)$

Here, $\mu$ is the coefficient of friction and $g$ is the acceleration due to gravity.

Substitute $40$ N for $F$ , $60$ kg for $m$ and $9.80$ m/s² for $g$ into equation (1) and solve to calculate the value of the coefficient of friction.

$40 N=\mu\times60 kg\times9.80 m/s^{2} \\~~~~~\mu=\frac{40 N}{60 kg\times9.80 m/s^{2}}\\~~~~~~~=0.068$

The formula to calculate the work done in overcoming the friction is given by

$W=Fd..........................(2)$

Here, $W$ is the work done and $d$ is the distance travelled.

Substitute $40$ N for $F$ and $8 m$ for $d$ into equation (2) to calculate the work done.

$W=40~N\times8~m\\~~~~= 320~J$

8 0

3 years ago

Select the correct answer.

denis-greek [22]

Answer:

D) 100 kilometres/hour.

Explanation :

Given -

Displacement = 200 km
Time taken = 2 hrs.

To find -

Average velocity of the car.

Solution -

★ Velocity = displacement/time

→ V = 200/2

→ v = 100 km/h

Therefore, the average velocity of the car is 100 km/h.

5 0

3 years ago