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2 years ago

Hey hiihhbdndkdkdjdjddjdj

Chemistry

2 answers:

tensa zangetsu [6.8K]2 years ago

8 0

Answer:

HEYYYY

Explanation:

grigory [225]2 years ago

7 0

Answer:

4 cups are about 0.25 gallons

Explanation:

To convert a cup measurement to a gallon measurement, divide the volume by the conversion ratio. The volume in gallons is equal to the cups divided by 16.

You might be interested in

Copper metal has a specific heat of 0.385 J/goC. Calculate the amount of heat required to raise the temperature of 22.8 g of Cu

Liula [17]

Answer is equal to 7.51 kJ

Q=mc(delta)T

4 0

1 year ago

HELPP!!!!!!!!!!

muminat

1. Mg + CuSO4 —> MgSO4 + Cu

=> Single displacement reaction

2. 2HCI + Mg(OH)2 —> MgCI2 + H2O

=> Acid - base reaction

3.AgNO3 + NaCI —> AgCI + NaNO3

=> Double displacement reaction

8 0

2 years ago

All of the following are considered anxiety disorders EXCEPT

kenny6666 [7]

obsessive compulsive disorder because OCD is a neurobiological disorder — not a condition that is caused by action or inaction.

5 0

3 years ago

What are two ways to change the solubility of a solute?

Anna11 [10]

Answer:

Change the temperature and pressure

Explanation:

In case we are analyzing the solubility of a salt in some solvent, raising the temperature would increase the solubility of a salt generally. In contrast, at lower temperatures the solubility of ionic salts would decrease.

Now, another variation of this scenario might be solubility of gases. According to Henry's Law, $S = k_Hp$ , meaning that the solubility of a gas is directly proportional to its partial pressure. Therefore, the greater the pressure, the greater the solubility of a gas.

4 0

3 years ago

Aluminum–lithium (Al–Li) alloys have been developed by the aircraft industry to reduce the weight and improve the performance of

gtnhenbr [62]

Answer:

The concentration of Li (in wt%) is 3,47g/mol

Explanation:

To obtain the 2,42g/cm³ of density:

2,42g/cm³ = 2,71g/cm³X + 0,534g/cm³Y (1)

Where X is molar fraction of Al and Y is molar fraction of Li.

X + Y = 1 (2)

Replacing (2) in (1):

Y = 0,13

Thus, X = 0,87

The weight of Al and Li is:

0,87*26,98g/mol = 23,4726 g of aluminium

0,13*6,941g/mol = 0,84383 g of lithium

The concentration of Li (in wt%) is:

0,84383g/(0,84383g+23,4726g) ×100= 3,47%

6 0

2 years ago