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Andrew [12]
3 years ago
11

Hey hiihhbdndkdkdjdjddjdj

Chemistry
2 answers:
tensa zangetsu [6.8K]3 years ago
8 0

Answer:

HEYYYY

Explanation:

grigory [225]3 years ago
7 0

Answer:

4 cups are about 0.25 gallons

Explanation:

To convert a cup measurement to a gallon measurement, divide the volume by the conversion ratio. The volume in gallons is equal to the cups divided by 16.

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What is the mass of 1.84 mol NaCl? Give your
Sphinxa [80]

Answer:

108 g

Explanation:

3 0
3 years ago
Some one help me please I'm stuck Show using two conversion factors how you would convert from 0.020 kg into mg.
julia-pushkina [17]

Answer:

=2.0x10^4mg

Explanation:

Hello there!

In this case, when performing units conversions involving two proportional factors we need to make sure we first convert to the base unit and then to the target one; thus, since 1 kg = 1000 g and 1 g = 1000 mg, we set up the following expression:

=0.020kg*\frac{1000g}{1kg} *\frac{1000mg}{1g} \\\\=2.0x10^4mg

Best regards!

4 0
3 years ago
A scientist dissolves 10 g of NaOH into 0.275 L of water. What is the
Damm [24]
The answer is 0.9091 M
5 0
3 years ago
In 4/2HE, what does the number 4 indicate?
11Alexandr11 [23.1K]

The number 4 in the 4/2He indicates the atomic mass number of helium.

Answer: Option 3

<u>Explanation: </u>

The elements present in periodic table generally represented as X_{Z}^{A}. Here X will be the element in the periodic table, A is the atomic mass number of the element X and Z is the atomic number of the element X.

So, the number 4 is the atomic mass number of He and He-4 is the stable isotope of helium which can also be termed as alpha particle.

               Mass number = number of protons + neutrons count.

Thus the number 4 denotes the Helium's atomic mass number.

6 0
3 years ago
How would you male 2.0L of O.100M sulfurice acid from a 12.0M stock bottle of sulfurice acid Calc, sketch, and write a summary s
ozzi

<u>Answer:</u> The volume of stock solution needed is 0.016 L

<u>Explanation:</u>

To calculate the volume of stock solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the stock solution

M_2\text{ and }V_2 are the molarity and volume of diluted solution

We are given:

M_1=12M\\V_1=?L\\M_2=0.10M\\V_2=2L

Putting values in above equation, we get:

12\times V_1=0.1\times 2\\\\V_1=0.016L

Hence, the volume of stock solution needed is 0.016 L

7 0
3 years ago
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