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Tema [17]
3 years ago
14

Does ice particles have high interparticle force of attraction? Justify your answer. please and

Chemistry
1 answer:
Schach [20]3 years ago
8 0

Answer:

¿Las partículas de hielo tienen una alta fuerza de atracción entre partículas? Justifica tu respuesta

Explanation:

Dichos contenidos están presentes en los currículos de Física y Química de la educación básica, con independencia del marco legal, pues introducen al alumno en el conocimiento químico de la materia. Aunque la teoría cinética molecular obvia la composición atómica de las partículas, no deja de ser un contenido deseable para introducir a los alumnos en el mundo de la química pues permite diferenciar y establecer relaciones entre los niveles macro, micro y simbólico de la materia.

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At what temperature and pressure can all three phases of water exist simultaneously?
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Which statement accurately describes nonrenewable energy sources?
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Answer:

a resource that cannot be replenished in a short period of time.

Explanation:

Nonrenewable energy sources take thousands to millions of years to replenish. hence the "nonrenewable".

5 0
3 years ago
assume you have a 500 g sample of a radioactive isotope with a half-life of 100 years. fill in the table showing how many grams
sweet-ann [11.9K]

Answer:

8.10 hours.

Explanation:

You start with 500.0g.

After the first half-life, you have 250.0g.

After the second, you have 125.0g.

After the third, you have 62.50g.

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Therefore, the elapsed time must be triple the length of one half-life.

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=

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3 years ago
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Using the thermodynamic information in the ALEKS Data tab, calculate the boiling point of titanium tetrachloride . Round your an
ddd [48]

Answer:

The boiling point is 308.27 K (35.27°C)

Explanation:

The chemical reaction for the boiling of titanium tetrachloride is shown below:

TiCl_{4(l)} ⇒ TiCl_{4(g)}

ΔH°_{f} (TiCl_{4(l)}) = -804.2 kJ/mol

ΔH°_{f} (TiCl_{4(g)}) = -763.2 kJ/mol

Therefore,

ΔH°_{f} = ΔH°_{f} (TiCl_{4(g)}) - ΔH°_{f} (TiCl_{4(l)}) = -763.2 - (-804.2) = 41 kJ/mol = 41000 J/mol

Similarly,

s°(TiCl_{4(l)}) = 221.9 J/(mol*K)

s°(TiCl_{4(g)}) = 354.9 J/(mol*K)

Therefore,

s° = s° (TiCl_{4(g)}) - s°(TiCl_{4(l)}) = 354.9 - 221.9 = 133 J/(mol*K)

Thus, T = ΔH°_{f} /s° = [41000 J/mol]/[133 J/(mol*K)] = 308. 27 K or 35.27°C

Therefore, the boiling point of titanium tetrachloride is 308.27 K or 35.27°C.

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The technology in the picture produces which energy conversion
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