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3 years ago

Does ice particles have high interparticle force of attraction? Justify your answer. please and

Chemistry

1 answer:

Schach [20]3 years ago

8 0

Answer:

¿Las partículas de hielo tienen una alta fuerza de atracción entre partículas? Justifica tu respuesta

Explanation:

Dichos contenidos están presentes en los currículos de Física y Química de la educación básica, con independencia del marco legal, pues introducen al alumno en el conocimiento químico de la materia. Aunque la teoría cinética molecular obvia la composición atómica de las partículas, no deja de ser un contenido deseable para introducir a los alumnos en el mundo de la química pues permite diferenciar y establecer relaciones entre los niveles macro, micro y simbólico de la materia.

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प्रश्न 5. 'पुष्प की अभिलाषा' कविता में पुष्प के दवारा क्या अभिलाषा व्यक्त की गई

Kay [80]

Please ask in English

4 0

3 years ago

Help!!!!!!!!!!!!!!!!!!

skad [1K]

The density of the sample : 0.827 g/L

<h3>Further explanation</h3>

In general, the gas equation can be written

$\large {\boxed {\bold {PV = nRT}}}$

where

P = pressure, atm , N/m²

V = volume, liter

n = number of moles

R = gas constant = 0.082 l.atm / mol K (P= atm, v= liter),or 8,314 J/mol K (P=Pa or N/m2, v= m³)

T = temperature, Kelvin

n= 1 mol

MW Neon = 20,1797 g/mol

mass of Neon :

$\tt mass=mol\times MW\\\\mass=1\times 20,1797 =20.1797~g$

The density of the sample :

$\tt \rho=\dfrac{m}{V}\\\\\rho=\dfrac{20,1797}{24.4}=0.827~g/L$

or We can use the ideal gas formula ta find density :

$\tt \rho=\dfrac{P\times MW}{RT}\\\\\rho=\dfrac{1\times 20.1797}{0.082\times 298}\\\\\rho=0.826~g/L$

8 0

3 years ago

The rate of a reaction increases as the temperature__________________. A. decreases B. increasesC. stays the same

KengaRu [80]

Answer:

1) B. increases

2) B. greater

3) C. Both A and B are correct

4) Activation energy

Explanation:

The rate of a chemical reaction is depend on temperature. If temperature increases, the chemical reaction also increases and vice versa. Fast reaction means which is completely in less time. So atoms in fast reaction have great activation energy and slow reaction have less activation energy. Collision occurs when the particles have energy to move and they collide in proper direction.

8 0

3 years ago

how many calories is in one peanut if the volume of water is 10 mL and the water temperature is rise 4 degrees celsius

liraira [26]

Answer:

40.02 calories

Explanation:

V = 10 mL = 10g

we know t went <em>up</em> by 4°C, this is our ∆t as it is a change.

Formula that ties it together: Q = mc∆t

where,

Q = energy absorbed by water

m = mass of water

c = specific heat of water (constant)

∆t = temperature change

Q = (10 g) x (4.186 J/g•°C) x (4°C)

Q = 167.44 J

Joules to Calories:

167.44 J x 1 cal/4.184 J = 40.02 calories

(makes sense as in image it is close to the value).

4 0

3 years ago

153 mL of 2.5 M HF is reacted with an excess of Ca(OH)2. How many grams of CaF2 will be produced?

Delvig [45]

Answer:

15 g

Explanation:

Data given:

amount of HF = 153 mL 2.5 M HF

amount of Ca(OH)₂ = Excess

grams of CaF₂ = ?

Reaction Given:

2HF + Ca(OH)₂ ------→ 2H₂O + CaF₂

Solution:

First we have to find number of moles of HF in 153 mL of 2.5 M HF

For this we will use following formula

Molarity = moles of solute / liter of solution

Rearrange above equation

moles of solute = Molarity x liter of solution . . . . . (1)

Put values in above equation (1)

moles of solute = 2.5 x 1 L

moles of solute = 2.5

So,

we come to know that there are 2.5 moles of solute (HF) in 1 L of solution

Now how many moles of solute will be present in 153 ml of solution

Convert 153 mL to Liter

1000 mL = 1 L

153 mL = 153/1000 = 0.153 L

Apply Unity Formula

2.5 moles HF ≅ 1 L solution

X moles of HF ≅ 0.153 L solution

moles of HF = 2.5 moles x 0.153 mL solution / 1 L solution

moles of HF = 0.383 moles

So, 153 mL contains 0.383 moles of HF

Now Look at the reaction:

2HF + Ca(OH)₂ ------→ 2H₂O + CaF₂

2 mol 1 mol

From the reaction we come to know that 2 moles of HF gives 1 mole of CaF₂ then how many moles of CaF₂ will be produced from o.383 moles of HF

Apply Unity Formula

2 moles HF ≅ 1 mole of CaF₂

0.383 moles of HF ≅ X moles of CaF₂

moles of CaF₂ = 0.383 moles x 1 mole / 2 mol

moles of CaF₂ = 0.192 moles

So, 0.192 moles of CaF₂ will be produced by 0.383 moles of HF

Now we will find mass of 0.192 moles of CaF₂

Formula will be used

mass in grams = no. of moles x molar mass . . . . . . . (2)

molar mass of CaF₂ = 40 + 2(19)

molar mass of CaF₂ = 40 + 38 = 78 g/mol

Put values in eq. 2

mass in grams = 0.192 x 78 g/mol

mass in grams = 14.976 g

rounding the value

mass in grams = 15 g

So,153 mL of 2.5 M HF is reacted with an excess of Ca(OH)₂ will produce 15 g of CaF₂.

6 0

4 years ago