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3 years ago

Calculate the number of milligrams to 0.425 kg

Chemistry

1 answer:

sp2606 [1]3 years ago

4 0

Answer:

Explanation:

as we know that 1kg =1,000,000 mg

therefore

0.425 kg= 0.425*1,000,000/1=425000

result:

0.425 kg contain 425000 mg

i hope this will help you

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QveST [7]

Answer:

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3 years ago

Solve: Turn off Show summary. Use the Choose reaction drop down menu to see other equations, and balance them. Check your answer

suter [353]

Answer: See below

Explanation:

To balance equations, you want to have the same amount of elements on the product and reactants side.

__Al+ __HCl→__AlCl₃+ __H₂

We see that there are 3 Cl on the products side and 1 on the reactants side, but there are 2 H on the product and 1 on reactant. To fulfill them both, let's put a 6 at HCl.

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Now that we have a 6 at HCl, we can fill in AlCl₃ and H₂.

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2Al+ 6HCl→ 2AlCl₃+ 3H₂

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Since we have 2 Cl on the products, we must put 2 on the reactants.

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7 0

3 years ago

A chemist must prepare 0.200 L of aqueous silver nitrate working solution. He'll do this by pouring out some aqueous silver nitr

jeyben [28]

A chemist must prepare 0.200 L of 1.00 M aqueous silver nitrate working solution. He'll do this by pouring out 1.82 mol/L aqueous silver nitrate stock solution into a graduated cylinder and diluting it with distilled water. How many mL of the silver nitrate stock solution should the chemist pour out?

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Explanation:

According to the dilution law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of stock silver nitrate solution = 1.82 M

$V_1$ = volume of stock silver nitrate solution = ?

$M_1$ = molarity of diluted silver nitrate solution = 1.00 M

$V_1$ = volume of diluted silver nitrate solution = 0.200 L

Putting in the values we get:

$1.82M\times V_1=1.00M\times 0.200L$

$V_1=0.110L$

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3 years ago

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