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nikitadnepr [17]
3 years ago
10

The density of benzene at 15 °c is 0.8787 g/ml. Calculate the mass of 0.1500 l of benzene at this temperature. Enter your answer

in terms of grams
Chemistry
1 answer:
Otrada [13]3 years ago
5 0

Answer:

131.8 g.

Explanation:

  • There is a relation that relates the density of the substance (d) to the mass (m) and the volume of the substance (V):

<u><em>d = m / V.</em></u>

d = 0.8787 g/ml.

V = 0.15 L x 1000 = 150 ml.

  • ∴ the mass of 0.15 L of benzene = d x V = (0.8787 g/ml) (150 ml) = 131.8 g.
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25 g of a chemical is dissolved in 75 g of water. What is the percent by mass concentration of this chemical
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Answer:

Three orbitals

Explanation:

The electronic configuration of carbon is given as follows;

1s²2s²2p²

Therefore, out of the six electrons of the carbon atoms, 4 fill the 1s and 2s orbitals with 2 electrons each, while the two remaining electrons are situated in the 2p orbital, with the electrons in the 2p orbital will remain unpaired such that they will have similar quantum numbers in accordance with Pauli exclusion principle.

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3 years ago
When the following oxidation–reduction reaction in acidic solution is balanced, what is the lowest whole-number coefficient for
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c. 8, product side

Explanation:

In order to balance a redox reaction we use the ion-electron method, which has the following steps:

Step 1: identify oxidation and reduction half-reaction.

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Reduction: Br⁻(aq) → Br₂(l)

Step 2: perform the mass balance adding H⁺ and H₂O where necessary

8 H⁺(aq) + MnO₄⁻(aq) → Mn²⁺(aq) + 4 H₂O(l)

2 Br⁻(aq) → Br₂(l)

Step 3: perform the electrical balance adding electrons where necessary.

8 H⁺(aq) + MnO₄⁻(aq) + 5 e⁻ → Mn²⁺(aq) + 4 H₂O(l)

2 Br⁻(aq) → Br₂(l) + 2 e⁻

Step 4: multiply both half-reactions by numbers that secure that the number of electrons gained and lost are the same.

2 × (8 H⁺(aq) + MnO₄⁻(aq) + 5 e⁻ → Mn²⁺(aq) + 4 H₂O(l))

5 × (2 Br⁻(aq) → Br₂(l) + 2 e⁻)

Step 5: add both half-reactions side to side.

16 H⁺(aq) + 2 MnO₄⁻(aq) + 10 e⁻ + 10 Br⁻(aq) → 2 Mn²⁺(aq) + 8 H₂O(l) + 5 Br₂(l) + 10 e⁻

16 H⁺(aq) + 2 MnO₄⁻(aq) + 10 Br⁻(aq) → 2 Mn²⁺(aq) + 8 H₂O(l) + 5 Br₂(l)

3 0
3 years ago
Some patterns of electron configuration are listed below. In each case, [G] stands for a noble-gas core and n, m, or o stand for
Nonamiya [84]

Answer:

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Explanation:

The outermost electronic configuration of an element shows the group to which it belongs in the periodic table as shown above in the answer. In addition, to that, we can be able to know from its electronic configuration, whether the element is a metal or not.

For instance;

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