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nikitadnepr [17]
2 years ago
10

The density of benzene at 15 °c is 0.8787 g/ml. Calculate the mass of 0.1500 l of benzene at this temperature. Enter your answer

in terms of grams
Chemistry
1 answer:
Otrada [13]2 years ago
5 0

Answer:

131.8 g.

Explanation:

  • There is a relation that relates the density of the substance (d) to the mass (m) and the volume of the substance (V):

<u><em>d = m / V.</em></u>

d = 0.8787 g/ml.

V = 0.15 L x 1000 = 150 ml.

  • ∴ the mass of 0.15 L of benzene = d x V = (0.8787 g/ml) (150 ml) = 131.8 g.
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sergeinik [125]

Answer : The formula for each of the following is:

(a) C_{22}H_{46}

(b) C_{17}H_{34}

(c) C_{13}H_{24}

Explanation :

  • Alkanes are hydrocarbon in which the carbon atoms are connected with single covalent bonds.

The general formula of alkanes is C_n H_{2n+2} where n is the number of the carbon atoms present in a molecule of alkane.

  • Alkenes are hydrocarbon in which the carbon atoms are connected with double covalent bonds.

The general formula of alkenes is C_n H_{2n} where n is the number of the carbon atoms present in a molecule of alkene.

  • Alkynes are hydrocarbon in which the carbon atoms are connected with triple covalent bonds.

The general formula of alkynes is C_n H_{2n-2} where n is the number of the carbon atoms present in a molecule of alkyne.

(a) An alkane with 22 carbon atoms

Putting n = 22 in the general formula of alkane, we get the formula of alkane as, C_{22}H_{2(22)+2} or C_{22}H_{46}

(b) An alkene with 17 carbon atoms

Putting n = 17 in the general formula of alkene, we get the formula of alkene as, C_{17}H_{2(17)} or C_{17}H_{34}

(c) An alkyne with 13 carbon atoms

Putting n = 13 in the general formula of alkyne, we get the formula of alkyne as, C_{13}H_{2(13)-2} or C_{13}H_{24}

3 0
3 years ago
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F
Katarina [22]

The statement is true in this situation is C. The size of Ffric is the same as the size of Fapp:

From the diagram, since the body is in equilibrium, the sum of vertical forces equals zero. Also, the sum of horizontal forces equal zero.

So, ∑Fx = 0 and ∑Fy = 0

Since Fapp acts in the negative x - direction and Ffric acts in the positive x - direction,

∑Fx = -Fapp + Ffric = 0

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Also, since Fgrav acts in the negative y - direction and Fnorm acts in the positive y - direction,

∑Fy = Fnorm + (-Fgrav) = 0

Fnorm - Fgrav = 0

Fnorm = Fgrav

So, we see that the size of Fapp <u>equals</u> size of Ffric and the size of Fnorm <u>equals</u> the size of Fgrav.

So, the correct option is C

The statement which is true in this situation is C. The size of Ffric is the same as the size of Fapp.

Learn more about equilibrium of forces here:

brainly.com/question/12980489

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