A particle smaller than an atom or a <span>cluster of such particles </span>
Answer:
The wire now has less (the half resistance) than before.
Explanation:
The resistance in a wire is calculated as:
![R=\alpha \frac{l}{s}](https://tex.z-dn.net/?f=R%3D%5Calpha%20%5Cfrac%7Bl%7D%7Bs%7D)
Were:
R is resistance
is the resistance coefficient
l is the length of the material
s is the area of the transversal wire, in the case of wire will be circular area (
).
So if the lenght and radius are doubled, the equation goes as follows:
![R=\alpha \frac{l}{\pi r^{2} } =\alpha \frac{2l}{\pi {(2r)}^{2} } =\alpha \frac{2l}{\pi 4 {r}^{2} }=\frac{1}{2} \alpha \frac{l}{\pi r^{2} }](https://tex.z-dn.net/?f=R%3D%5Calpha%20%5Cfrac%7Bl%7D%7B%5Cpi%20r%5E%7B2%7D%20%7D%20%3D%5Calpha%20%5Cfrac%7B2l%7D%7B%5Cpi%20%7B%282r%29%7D%5E%7B2%7D%20%7D%20%3D%5Calpha%20%5Cfrac%7B2l%7D%7B%5Cpi%204%20%7Br%7D%5E%7B2%7D%20%7D%3D%5Cfrac%7B1%7D%7B2%7D%20%5Calpha%20%5Cfrac%7Bl%7D%7B%5Cpi%20r%5E%7B2%7D%20%7D)
So finally because the circular area is a square function, the resulting equation is half of the one before.
Answer:
2.11 seconds
Explanation:
We use the kinematic equation for the velocity in a constantly accelerated motion under the acceleration of gravity (g):
![v_f=v_i-g*t\\-5.2 = 15.5 - 9.8\,t\\9.8 \,t= 15.5 + 5.2\\t = 20.7/9.8\\t = 2.11 \,\,sec](https://tex.z-dn.net/?f=v_f%3Dv_i-g%2At%5C%5C-5.2%20%3D%2015.5%20-%209.8%5C%2Ct%5C%5C9.8%20%5C%2Ct%3D%2015.5%20%2B%205.2%5C%5Ct%20%3D%2020.7%2F9.8%5C%5Ct%20%3D%202.11%20%5C%2C%5C%2Csec)
Answer:
The net charge on the shell is 30x10^-9C
Explanation:
Pls see attached file