3 years ago

Equation for fluid density

1 answer:

MrMuchimi3 years ago

7 0

<span> (ρ = m / V) hope this helps...:)</span>

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VashaNatasha [74]

In order to solve this problem it is necessary to apply the concepts related to intensity and specifically described in Malus's law.

Malus's law warns that

$I = I_0 cos^2\theta$

Where,

$\theta=$ Angle between the analyzer axis and the polarization axis

$I_0 =$ Intensity of the light before passing through the polarizer

The intensity of the beam from the first polarizer is equal to the half of the initial intensity

$I = \frac{I_0}{2}$

Replacing with our the numerical values we get

$I = \frac{46}{2}$

$I = 23W/m^2$

Therefore the intensity of the light that emerges from the filter is $23W/m^2$

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