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steposvetlana [31]
3 years ago
11

Equation for fluid density

Physics
1 answer:
MrMuchimi3 years ago
7 0
<span> (ρ = m / V) hope this helps...:)</span>
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The force between a pair of .005 charges is 750 N. What is the distance between them?
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Question: The force between a pair of 0.005 C is 750 N. What is the distance between them?

Answer:

17.32 m

Explanation:

From coulomb's Law,

F = kqq'/r²........................... Equation 1

Where F = Force between the force, q' and q = both charges respectively, k = coulomb's constant, r = distance between both charges.

make r the subject of the equation above

r = √(kqq'/F)..................... Equation 2

From the question,

Given: q = q' = 0.005 C, F = 750 N

Constant: k = 9.0×10⁹ Nm²/C².

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r = √(9.0×10⁹×0.005×0.005/750)

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