When light moves from air to glass, part of the light is reflected and part of it is refracted. In the image, which ray shows re
fraction?
2 answers:
You have not provided the diagram, therefore, I cannot provide an exact answer.
However, I will try to help by explaining how to solve this problem.
When light moves from air to glass:
1- part of the light is reflected back into the air where the angle of incidence is equal to the angle of reflection
2- part of the light enters the water and refracts. The angle of refraction can be calculated using Snell's law.
In a diagram, the reflected ray would be the one getting back into air while the refracted ray would be the one entering the water.
You can check the attached diagram for further illustrations.
Hope this helps :)
However, I will try to help by explaining how to solve this problem.
When light moves from air to glass:
1- part of the light is reflected back into the air where the angle of incidence is equal to the angle of reflection
2- part of the light enters the water and refracts. The angle of refraction can be calculated using Snell's law.
In a diagram, the reflected ray would be the one getting back into air while the refracted ray would be the one entering the water.
You can check the attached diagram for further illustrations.
Hope this helps :)
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Explanation
If you graph the force on an object as a function of the position of that object, then the area under the curve will equal the work done on that object, so we need to find the area under the function to find the work
Step 1
find the area under the function.
so
Area:
so
therefore, the answer is
I hope this helps you
When a force causes a body to move, work is done on the object by the force. Work is the measure of the energy transfer when a force 'F' moves an object through a distance 'd'. So we say that energy is transferred from one energy store to another when work is done, and therefore, energy transferred = work done.
Answer:
a) v = 19,149.6 m/s
b) f = 95%
c) t = 346.5min
Explanation:
First put all values in metric units:
The equation of motion you need is:
where is the final velocity, a is acceleration and t is time in hours.
Since the spaceship starts from 0 velocity:
Next, you need to calculate the distances traveled on each interval, considering that both starting and final intervals travel the same distance because the acceleration and time are equal. For this part you need the next motion equation:
solving for first and last interval:
Since the spaceship starts and finish with 0 velocity:
Then the ship traveled at constant speed, which means that it traveled:
Which in percentage is 95% of the trip.
to calculate total time you need to calculate the time used during constant speed:
That added to the other interval times: