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3 years ago

12

Creates an image that appears upside down behind the focal point

1 answer:

zheka24 [161]3 years ago

8 0

An image that appears upside down behind the focal point is an image that is reflected on a concave mirror. Mirrors reflect different kinds of images based on the placement of an object that is reflected towards it. There are two kinds of mirrors, concave and a convex mirrors, the latter makes objects seem smaller and farther than where it is exactly.

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A helicopter goes straight up 500m from a landing pad. It then goes north 20m. Then it goes down 452m. a) What is the displaceme

gavmur [86]

Answer:

a

x-component $20 \ m$

y-component $500 - 452 = 48 \ m$

b

Magnitude $d = 52 \ m$

direction is $\theta = 67.4^o$

Explanation:

From the question we are told that

The first vertical distance is $y_1 = 500 \ m$

The first horizontal distance is $x = 20 \ m$

The second vertical distance is $y_2 = 452 \ m$

Generally the displacement is

x-component $20 \ m$

y-component $500 - 452 = 48 \ m$

Generally the helicopters displacement is mathematically evaluated as

$d = \sqrt{ x- component ^2 + y- component ^2 }$

$d = \sqrt{ 20t ^2 + 48 ^2 }$

$d = 52 \ m$

The direction is the angle the displacement of the helicopter makes with the horizontal which is mathematically evaluated as

$\theta = tan ^{-1}[ \frac{48}{20}]$

=> $\theta = tan ^{-1}[ 2.4 ]$

=> $\theta = 67.4^o$

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