Question

S- 2500m

Answer 1

Answer:

1632 Hz

Explanation:

We'll begin by calculating the frequency of each wave. This can be obtained as follow:

1st wave:

Velocity (v) = 340 m/s.

Wavelength 1 (λ₁) = 5 m

Frequency 1 (f₁) =?

v = λ₁f₁

340 = 5 × f₁

Divide both side by 5

f₁ = 340 / 5

f₁ = 68 Hz

2nd wave:

Velocity (v) = 340 m/s.

Wavelength 2 (λ₂) = 0.2 m

Frequency 2 (f₂) =?

v = λ₂f₂

340 = 0.2 × f₂

Divide both side by 0.2

f₂ = 340 / 0.2

f₂ = 1700 Hz

Finally, we shall determine the difference in the frequency of both waves.

This can be obtained as follow:

Frequency 1 (f₁) = 68 Hz

Frequency 2 (f₂) = 1700 Hz

Difference =?

Difference = f₂ – f₁

Difference = 1700 – 68

Difference = 1632 Hz