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Natalija [7]
3 years ago
13

S- 2500m

Chemistry
1 answer:
natulia [17]3 years ago
8 0

Answer:

1632 Hz

Explanation:

We'll begin by calculating the frequency of each wave. This can be obtained as follow:

1st wave:

Velocity (v) = 340 m/s.

Wavelength 1 (λ₁) = 5 m

Frequency 1 (f₁) =?

v = λ₁f₁

340 = 5 × f₁

Divide both side by 5

f₁ = 340 / 5

f₁ = 68 Hz

2nd wave:

Velocity (v) = 340 m/s.

Wavelength 2 (λ₂) = 0.2 m

Frequency 2 (f₂) =?

v = λ₂f₂

340 = 0.2 × f₂

Divide both side by 0.2

f₂ = 340 / 0.2

f₂ = 1700 Hz

Finally, we shall determine the difference in the frequency of both waves.

This can be obtained as follow:

Frequency 1 (f₁) = 68 Hz

Frequency 2 (f₂) = 1700 Hz

Difference =?

Difference = f₂ – f₁

Difference = 1700 – 68

Difference = 1632 Hz

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What is the empirical formula of a compound composed of 3.25% hydrogen ( H ), 19.36% carbon ( C ), and 77.39% oxygen ( O ) by ma
Montano1993 [528]

Answer:

The answer to your question is C₂HO₃

Explanation:

Data

Hydrogen = 3.25%

Carbon = 19.36%

Oxygen = 77.39%

Process

1.- Write the percent as grams

Hydrogen = 3.25 g

Carbon = 19.36 g

Oxygen = 77.39 g

2.- Convert the grams to moles

                     1 g of H ----------------- 1 mol

                   3,25 g of H -------------  x

                     x = (3.25 x 1) / 1

                     x = 3.25 moles

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                     19.36 g of C ----------  x

                     x = (19.36 x 1) / 12

                     x = 1.61 moles

                     16g of O --------------- 1 mol

                     77.39 g of O ---------  x

                      x = (77.39 x 1)/16

                      x = 4.83

3.- Divide by the lowest number of moles

Carbon = 3.25/1.61 = 2

Hydrogen = 1.61/1.61 = 1

Oxygen = 4.83/1.61 = 3

4.- Write the empirical formula

                        C₂HO₃

4 0
3 years ago
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Hope this helps!

8 0
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