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Kaylis [27]
2 years ago
14

can someone please help me with this question, it's for my lab report. I tried my best but failed to do the calculation. please

it's an emergency, just do the best you can, even if you're not 100% sure with your answer, atleast it will give me an idea also where to start. Thank you

Chemistry
1 answer:
Dahasolnce [82]2 years ago
3 0

YOU BETTER MARK ME BRAINLIEST if someone else answers!!!!

When the two substances are mixed, we see an increase in the temperature,

The flat horizontal line at the beginning of the graph tells us the initial temperature of mixing the two substance.

The initial temperature of mixing is ≈22.5 oC

and, final temperature would be the next flat horizontal line ≈32.5 oC from the given graph

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Answer:

i feel like the answer is A

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2 years ago
If an ideal gas has a pressure of 4.03 atm,
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Answer:

PV=nRT where P=pressure in atm, V=volume is liters, n=numbber of moles, R=gas constant, 0.08206 L-atm/mole KL, and T=temperature in K (273 + C).  So (5.67atm)(99.39L)=n(0.08206 L-atm/mol.K)(328.94K), solve for n, the number of moles, n=20.9 moles.

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7 0
2 years ago
The molecular mass of methyl ethanoate is 75.1 amu . calculate the molecular mass of propanoic acid, an isomer of methyl ethanoa
iren [92.7K]
Molecular Formula of Propanoic Acid is....

                                                C₃H₆O₂
Where;

Atomic Mass of C  =  12

Atomic Mass of H  =  1

Atomic Mass of O  =  6

Substituting Atomic Masses in molecular formula,

                                                (12)₃ + (1)₆ + (16)₂

                                                   36  +  6  +  32

                                                        74 g/mol

Result:
            
Molecular Mass of Propanoic Acid is 74 g/mol. Structure of Methyl Ethanoate and Propanoic Acid are as follow,

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3 years ago
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2 years ago
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<h3>Further explanation</h3>

Acetic acid = weak acid

\tt [H^+]=\sqrt{Ka.M}

Ka = acid ionization constant

M = molarity

Ka for Acetic acid(CH₃COOH) : 1.8 x 10⁻⁵

\tt [H^+]=\sqrt{1.8\times 10^{-5}\times 0.222}\\\\=0.001998=1.998\times 10^{-3}

\tt pH=3-log~1.998=2.7

7 0
3 years ago
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