Answer:
PV=nRT where P=pressure in atm, V=volume is liters, n=numbber of moles, R=gas constant, 0.08206 L-atm/mole KL, and T=temperature in K (273 + C). So (5.67atm)(99.39L)=n(0.08206 L-atm/mol.K)(328.94K), solve for n, the number of moles, n=20.9 moles.
Explanation:
Molecular Formula of Propanoic Acid is....
C₃H₆O₂Where;
Atomic Mass of C = 12
Atomic Mass of H = 1
Atomic Mass of O = 6
Substituting Atomic Masses in molecular formula,
(12)₃ + (1)₆ + (16)₂
36 + 6 + 32
74 g/mol
Result:
Molecular Mass of Propanoic Acid is 74 g/mol. Structure of Methyl Ethanoate and Propanoic Acid are as follow,
B.
Delta G is negative and Delta S is positive.
pH=2.7
<h3>Further explanation</h3>
Acetic acid = weak acid
![\tt [H^+]=\sqrt{Ka.M}](https://tex.z-dn.net/?f=%5Ctt%20%5BH%5E%2B%5D%3D%5Csqrt%7BKa.M%7D)
Ka = acid ionization constant
M = molarity
Ka for Acetic acid(CH₃COOH) : 1.8 x 10⁻⁵
![\tt [H^+]=\sqrt{1.8\times 10^{-5}\times 0.222}\\\\=0.001998=1.998\times 10^{-3}](https://tex.z-dn.net/?f=%5Ctt%20%5BH%5E%2B%5D%3D%5Csqrt%7B1.8%5Ctimes%2010%5E%7B-5%7D%5Ctimes%200.222%7D%5C%5C%5C%5C%3D0.001998%3D1.998%5Ctimes%2010%5E%7B-3%7D)
