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Paha777 [63]
3 years ago
13

According to a survey of 1000 families of any town in 2010 A.D.,794 families have radio and 187 families have television.lf 63 f

amilies do not have any one of them,then how many families will have both radio and television?Find it.​
Mathematics
1 answer:
hjlf3 years ago
4 0

Answer:

Number of families will have both radio and television = 44

Step-by-step explanation:

Given:

Number of family have radio = 794

Number of family have TV = 187

Number of family haven't both = 63

Find:

Number of families will have both radio and television

Computation:

Number of families will have Tv or radio = 1,000 - 63

Number of families will have Tv or radio = 937

Number of family have one of them = 794 + 187

Number of family have one of them = 981

Number of families will have both radio and television = 981 - 937

Number of families will have both radio and television = 44

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Let the number of chocolate chips in a certain type of cookie have a Poisson distribution. We want the probability that a cookie
ludmilkaskok [199]

Answer:

\lambda \geq 6.63835

Step-by-step explanation:

The Poisson Distribution is "a discrete probability distribution that expresses the probability of a given number of events occurring in a fixed interval of time or space if these events occur with a known constant mean rate and independently of the time since the last event".

Let X the random variable that represent the number of chocolate chips in a certain type of cookie. We know that X \sim Poisson(\lambda)

The probability mass function for the random variable is given by:

f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...

And f(x)=0 for other case.

For this distribution the expected value is the same parameter \lambda

E(X)=\mu =\lambda

On this case we are interested on the probability of having at least two chocolate chips, and using the complement rule we have this:

P(X\geq 2)=1-P(X

Using the pmf we can find the individual probabilities like this:

P(X=0)=\frac{e^{-\lambda} \lambda^0}{0!}=e^{-\lambda}

P(X=1)=\frac{e^{-\lambda} \lambda^1}{1!}=\lambda e^{-\lambda}

And replacing we have this:

P(X\geq 2)=1-[P(X=0)+P(X=1)]=1-[e^{-\lambda} +\lambda e^{-\lambda}[]

P(X\geq 2)=1-e^{-\lambda}(1+\lambda)

And we want this probability that at least of 99%, so we can set upt the following inequality:

P(X\geq 2)=1-e^{-\lambda}(1+\lambda)\geq 0.99

And now we can solve for \lambda

0.01 \geq e^{-\lambda}(1+\lambda)

Applying natural log on both sides we have:

ln(0.01) \geq ln(e^{-\lambda}+ln(1+\lambda)

ln(0.01) \geq -\lambda+ln(1+\lambda)

\lambda-ln(1+\lambda)+ln(0.01) \geq 0

Thats a no linear equation but if we use a numerical method like the Newthon raphson Method or the Jacobi method we find a good point of estimate for the solution.

Using the Newthon Raphson method, we apply this formula:

x_{n+1}=x_n -\frac{f(x_n)}{f'(x_n)}

Where :

f(x_n)=\lambda -ln(1+\lambda)+ln(0.01)

f'(x_n)=1-\frac{1}{1+\lambda}

Iterating as shown on the figure attached we find a final solution given by:

\lambda \geq 6.63835

4 0
3 years ago
Determine the number of Solutions for the system of equations y = 2x + 3 and y = 2x +3
vampirchik [111]

Answer:

:/

Step-by-step explanation:

:/

7 0
3 years ago
Write two expressions to show w increased by 4. Then, draw models to prove that both expressions represent the same thing.
Vinil7 [7]

Answer:Answer:

w + 4 and 4 + w

Step-by-step explanation:

Given phrase,

w is increased by 4,

That is, w + 4

By the commutative property of addition,

The expression would be,

4 + w

For drawing a model that shows w + 4

Take two boxes in which first shows w and second shows 4 and add them,

Similarly, for showing 4 + w, take first box that shows 4 and second box that shows w then add them.

Step-by-step explanation:

7 0
3 years ago
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What is f(−3) for the function f(a)=−2a2−5a+4?
andriy [413]

Answer:

i believe the answer is 1

Step-by-step explanation:

4 0
3 years ago
Answer this question​
Stells [14]

Answer:

\huge\boxed{width=12cm}

Step-by-step explanation:

l-length\\w-width\\P-perimeter

The formula of perimeter of the rectangle:

P=2l+2w=2(l+w)

Substitute:

l=6w\\\\P=168cm

168=2(6w+w)\\168=2(7w)\\168=14w\qquad|\text{divide both sides by 14}\\\\\dfrac{168}{14}=\dfrac{14w}{14}\\\\12=w\Rightarrow w=12(cm)

3 0
3 years ago
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