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Serga [27]
3 years ago
5

Iron-59 has a half-life of 45.1 days. How old is an iron nail if the Fe-59 content is 25% that of a new sample of iron? Show all

calculations leading to a solution.
Chemistry
1 answer:
alexdok [17]3 years ago
4 0

Answer:  

90.2 da

Explanation:  

The <em>half-life</em> of iron-59 (45.1 da) is the time it takes for half the Fe to decay.  

After one half-life, half (50 %) of the original amount will remain.  

After a second half-life, half of that amount (25 %) will remain, and so on.  

We can construct a table as follows:  

  No. of    Time    Percent       Fraction

<u>half-lives</u>  <u>days</u>   <u>remaining</u>   <u>remaining </u>

      1           45.1         50                 ½

      2          90.2        25                 ¼

      3          135           12.5              ⅛

      4          180            6.25           ¹/₁₆

We see that 25 % remains after two half-lives or 90.2 da.

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Answer:

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Explanation:

Step 1: Find the symbols for the substances

For copper, see your periodic table. Copper is "Cu".

For hydroxide, see your polyatomic ions chart. Hydroxide is "OH".

Step 2: Find the charges for each element.

Copper (II)'s charge is 2, which is the roman numerals in the brackets.

Hydroxide's charge is -1.

Charges are written as superscripts. You do not need to write "1".

In formulas, write the positively charged atom first.

Cu²⁺(OH)⁻   Put brackets around hydroxide because it has 2 elements.

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The number of atoms that an element has is the same as its partner's charge.

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You do not need to write the "1" for atoms.

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