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Advocard [28]
3 years ago
14

Which statement best describes the organelles in a cell

Chemistry
1 answer:
Bas_tet [7]3 years ago
5 0

Answer:

(2) Organelles must work together and their

activities must be coordinated

Explanation:

Organelles are usually located in cells. They are saddled with the role of performing specific functions in the cells for the overall functioning of life. In eukaryotic cells, the organelles are membrane bounded but in prokaryotic or primitive cells such is not the case.

Examples of cell organelles are ribosome, food vacuole, nucleus e.t.c. Just like organs in the body, organelles must work together in order to enhance life.

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Which of the following ions is formed when an acid is dissolved in a solution?
kiruha [24]

Answer:

  • <u><em>H⁺</em></u>

Explanation:

There are three definitions of acids: Arrhenius, Bronsted - Lowry, and Lewis.

An Arrhenius acid is a substance that when dissolved in water will release a proton (H⁺ or hdyronoum, H₃O⁺) in solution.

The definition of Bronsted-Lowry is not limited to aqueous solution: an acid is a substance that releases protons in any solvent. So it includes, the Arrhenius acids but also other acids.

The Lewis Acid definition is wider. It includes both Arrhenius and Bronsted-Lowry acids and other substances that do not release protons. A Lewis acid is a substance that accepts an electron pair.

Thus, <em>when an acid is dissolved in a solution, following Bronsted-Lowry definition, </em><u><em>H⁺ ions are formed.</em></u>

7 0
3 years ago
How much hbro must be added to 1l of pure water to make a solution with a ph of 4.25? ka = 2.00 × 10−9 ?
RUDIKE [14]
Answer is: 153.52 grams of hypobromous acid <span>must be added.
</span>Chemical dissociation: HBrO ⇄ H⁺ + BrO⁻.
pH = 4.25.
pH = -log[H⁺].
[H⁺] = 10∧(-pH).
[H⁺] = 10∧(-4.25).
[H⁺] = [BrO⁻] = 5.62·10⁻⁵ M.
Ka = [H⁺] · [BrO⁻] / [HBrO].
2.00·10⁻⁹ = (5.62·10⁻⁵ M)² / [HBrO].
[HBrO] = 3.16·10⁻⁹ M² / 2.00·10⁻⁹.
[HBrO] = 1.58 M.
m(HBrO) = n(HBrO) · M(HBrO).
m(HBrO) = 1.58 mol · 96.91 g/mol.
m(HBrO) = 153.52 g.
3 0
4 years ago
What is the empirical formula of a compound with 35.94% aluminum and 64.06% sulfur
Sunny_sXe [5.5K]

                        Al                                               S

    1)            <u>  35.94  </u>    =1.33111                     <u>  64.06 </u>     = 2.001875

                       27                                               32

    2)          =    <u> 1.33111 </u>                                 = <u>  2.001875  </u>

                     1.33111                                         1.33111

                 

    3)         =   ( 1 ) × 2                                     =    ( 1.5 ) ×2

    4)         =  2                                                =   3

                     Empirical Formula = Al2S3

1) Divide the percentage given in question by the Relative Atomic Mass (RAM)

of the given elements.

2) When you find the answers of the first part of question, divide these once again but this time, by the lowest number you found in part 1.

3) and 4) Write down the values. If you get a decimal which is in between 0.3-0.7 (including the 0.3 and 0.7), you cannot make it a whole number by rounding of. Therefore, multiply the decimal with a whole number until you get a whole number as your answer. In this question, when you multiply 1.5 by 2, the answer is 3 which is a whole number. Multiply the other whole number by the same number as that you multiplied for 1.5. And use these numbers in part 4 to make the empirical formula which is Aluminium Sulfide (Al2S3)

Hope this helps you :)))

Please give this a brainliest

6 0
3 years ago
In the following reaction, how many liters of carbon dioxide will be produced if 250 liters of oxygen is used in the combustion
love history [14]
The balanced reaction would be:<span>

C12H22O11 + 12O2 = 12CO2 + 11H2O

We are given the amount of oxygen used in the combustion. This will be the starting point of our calculation. We use the ideal gas equation to find for the number of moles.

n = PV / RT = 1.00(250 L) / (0.08206 atm L/mol K ) 273 K
n= 11.16 mol O2

</span>11.16 mol O2<span> (12 mol CO2 / 12 mol O2) = 11.16 mol CO2

V = nRT/P =</span>11.16 mol CO2<span> x 273 K x 0.08206 atm L/mol K / 1 atm
V=250 L</span>
7 0
4 years ago
Separation of mixture by gravity of sodium carbonat into calcium chloride​
Natali5045456 [20]

By combining aqueous solutions of calcium chloride and sodium carbonate, a solid calcium carbonate is produced.  The  CaCO 3  is trapped by the paper which forms as a precipitate, but the  NaCl  passes through the filter paper with the water.

<u>Explanation</u>:

  • In gravity separation, a combination of two incompatible liquids can be separated by using a separating funnel. The operation is based on the variation within the density of the liquids. The heavier liquid that settles down is drained out first from the funnel into the beaker, and then the lighter liquid is drained out into another beaker.
  • Filtration is used to separate a substance from a mixture because one is insoluble and the other is soluble. By combining aqueous solutions of calcium chloride and sodium carbonate, solid calcium carbonate is produced.

                CaCl 2 (aq) + Na 2 CO 3 (aq) → CaCO 3 (s) + 2NaCl(aq)

  • A filter paper is inserted in a funnel and the mixture may be poured through a funnel. The NaCl is passed through the filter paper with the water but CaCO3 is trapped by the paper which forms the precipitate.
8 0
4 years ago
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