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forsale [732]
3 years ago
14

Water that fills the cracks and spaces in underground soil and rock layers is calleda. salt water.

Chemistry
1 answer:
algol [13]3 years ago
8 0
The answer is groundwater
You might be interested in
How do particles in a solid move?
satela [25.4K]

Answer:

The particles in a solid vibrate in place.

Explanation:

The particles in a solid are close and tightly packed together so they have no room to flow past each other like the particles in a liquid can.

Hope this helps!

8 0
3 years ago
If you have 5.42 x 1024 aluminum atoms, approximately how many moles is that
sattari [20]

Answer:

<h2>9.00 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{5.42 \times  {10}^{24} }{6.02 \times {10}^{23} }  \\  = 9.0033

We have the final answer as

<h3>9.00 moles</h3>

Hope this helps you

4 0
3 years ago
Suppose you have a mixture of solid mg(oh)2 and baso4, how do you separate the mixture
Step2247 [10]
This separation technique is a 4-step procedure. First, add H₂SO₄ to the solution. Because of common ion effect, BaSO₄ will not react, only Mg(OH)₂.

Mg(OH)₂ + H₂SO₄ → MgSO₄ + 2 H₂O

The aqueous solution will now contain MgSO₄ and BaSO₄. Unlike BaSO₄, MgSO₄ is soluble in water. So, you filter out the solution. You can set aside the BaSO₄ on the filter paper. To retrieve Mg(OH)₂, add NaOH.

MgSO₄ + 2 NaOH = Mg(OH)₂ + Na₂SO₄

Na₂SO₄ is soluble in water, while Mg(OH)₂ is not. Filter this solution again. The Mg(OH)₂ is retrieved in solid form on the filter paper.
5 0
3 years ago
ccording to all known laws of aviation, there is no way a bee should be able to fly. Its wings are too small to get its fat litt
drek231 [11]

Answer:

The bee's energy output can be calculated directly, and related to its size. it only needs enough air resistance to counter its weight and enough power in its wings to sustain this resistance. it bee like that.

4 0
3 years ago
A metal, M, forms an oxide having the formula MO2 containing 59.93% metal by mass. Determine the atomic weight in g/mole of the
Damm [24]

Answer:

See solution.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to set up the formula for the calculation of the by-mass percentage of the metal:

\%  M=\frac{m_M}{m_M+2*m_O}*100 \%\\\\59.93\%  =\frac{m_M}{m_M+32.00}*100 \%

Thus, we solve for the molar mass of the metal to obtain:

59.93\% (m_M+32.00) =m_M*100 \%\\\\m_M*59.93\% +1917.76\% =m_M*100 \%\\\\m_M=47.86g/mol

For the subsequent problems, we proceed as follows:

a.

4.00gO_2*\frac{1molO_2}{32.00gO_2}=0.125molO_2

b.

0.400molH_2S*\frac{2molH}{1molH_2S}*\frac{6.022x10^{23}atomsH}{1molH}=4.82x10^{23}atomsH

c.

0.235gNH_3*\frac{1molNH_3}{17.03gNH_3} *\frac{3molH}{1molNH_3}*\frac{6.022x10^{23}atomsH}{1molH}=2.49x10^{22}atomsH

Regards!

7 0
3 years ago
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