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Ber [7]
3 years ago
15

A thermometer containing 0.10 g of mercury is cooled from 15 degrees celsius to 8.5 degrees celcius. How much energy left the me

rcury in this process?
Physics
1 answer:
loris [4]3 years ago
5 0

To solve this exercise we will use the concept related to heat loss which is mathematically given as

Q = mC_p \Delta T

Where,

m = mass

C_p= Specific Heat

\Delta T = Change in temperature

Replacing with our values we have that

m = 0.1g

C_p = 139J/Kg\cdot K \rightarrow Specific heat of mercury

\Delta T = 8.5\°C-15\°C = -6.5\°C \Rightarrow -6.5K

Replacing

Q = (0.1*10^3)(138)(-6.5)\\Q = -0.09J

Therefore the heat lost by mercury is 0.09J

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A small lead ball, attached to a 1.10-m rope, is being whirled in a circle that lies in the vertical plane. The ball is whirled
hjlf

Answer:

1.84 m

Explanation:

For the small lead ball to be balanced at the tip of the vertical circle just before it is released, the reaction force , N equal the weight of the lead ball W + the centripetal force, F. This normal reaction ,N also equals the tension T in the string.

So, T = mg + mrω² = ma where m = mass of small lead ball, g = acceleration due to gravity = 9.8 m/s², r = length of rope = 1.10 m and ω = angular speed of lead ball = 3 rev/s = 3 × 2π rad/s = 6π rad/s = 18.85 rad/s and a = acceleration of normal force. So,

a = g + rω²

= 9.8 m/s² + 1.10 m × (18.85 rad/s)²

= 9.8 m/s² + 390.85 m/s²

= 400.65 m/s²

Now, using v² = u² + 2a(h₂ - h₁)  where u = initial velocity of ball = rω = 1.10 m × 18.85 rad/s = 20.74 m/s, v = final velocity of ball at maximum height = 0 m/s (since the ball is stationary at maximum height), a = acceleration of small lead ball = -400.65 m/s² (negative since it is in the downward direction of the tension), h₁ = initial position of lead ball above the ground = 1.3 m and h₂ = final position of lead ball above the ground = unknown.

v² = u² + 2a(h₂ - h₁)

So, v² - u² = 2a(h₂ - h₁)

h₂ - h₁ =  (v² - u²)/2a

h₂ =  h₁ + (v² - u²)/2a

substituting the values of the variables into the equation, we have

h₂ =  1.3 m + ((0 m/s)² - (20.74 m/s)²)/2(-400.65 m/s²)

h₂ =  1.3 m + [-430.15 (m/s)²]/-801.3 m/s²

h₂ =  1.3 m + 0.54 m

h₂ =  1.84 m

7 0
2 years ago
Unlike hard disks, which use magnetic charges to represent 1s and 0s, _____ use reflected light.
dimaraw [331]

Answer:

Unlike hard disks, which use magnetic charges to represent 1s and 0s, Compact Disks, DVD's or Blue Rays use reflected light.

Explanation:

The way CD's work is that they are hit by a laser beam which is reflected on the surface of the disc. These disks have some valleys and mountains that reflect light differently so the CD player will interpret these differences in reflection as data which will then be turned into music, videos or computer files.

5 0
2 years ago
A mover hoists a 200 kg piano from the ground to a height of 10 m using a single pulley. What was the change in the pianos energ
RideAnS [48]
P.E= Mass x gravity x height   (standard gravity = 10m/s approaximately)
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7 0
3 years ago
Read 2 more answers
What are spooky rays? How were they discovered? How are they related to visible light?​
trapecia [35]
<h2>What are spooky rays? :Spooky rays are Halloween; Spooky mystic background light beams rays.</h2>

<h2>How was spooky rays discovered; In 1895,a German Engineer Wilhelm Röntgen, was experimenting with making cathode rays .His device was blacked out.But he noticed a piece of cardboard painted with barium platinocyanide flouresced when it was placed near the cathode ray tube.</h2>

<h2>How are they related to visible light?: This occurs when two particles are inextricably linked.</h2>

5 0
3 years ago
Monochromatic light (vacuum = 612 nm) shines on a soap film (n = 1.33) that has air on either side of it. The light strikes the
weeeeeb [17]

Answer:

t  =   110.079 nm

Explanation:-

we know that

for constructive interference in thin film

2nt = (m + (1/2))λ

where, n is refractive index

for minimum thickness m =0

2nt = λ /2

thickness   t   = λ / 4n

Here  

wavelength of light, λ = 612*10^{-9} m

refractive indices = 1.393t   = \frac{(612*10^{-9})}{(4*1.33)}t   =   115.03*10^{-9} m

t  =   110.03 nm

4 0
3 years ago
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