The average current passing through a device is given by:
I = Q/Δt
I is the average current
Q is the amount of charge that has passed through the device
Δt is the amount of elapsed time
Given values:
Q = 4.00C
Δt = 4.00hr = 14400s
Plug in the values and solve for I:
I = 4.00/14400
I = 0.000277777778A
I = 0.278mA
Explanation:
Let's look at the forces on the two axes:
Substituting (2) into (1) and solving for , we get
0.32 km
How to reach the answer:
The formula below provides the tsunami's speed in response to the query.
s = 356√d
when the tsunami's speed is 200 km/h, the equation's "s" is changed to "200," and the equation of speed is then expressed as follows.
200 = 356√d
The equation can be changed to compute the depth of the water as,
√d = 200÷356
√d = 0.562
Now on squaring both sides:
(√d)² = (0.562)²
d = (0.562)² = 0.316 or 0.32
Therefore the approximate depth of water for a tsunami travelling at 200km/h is 0.32 km
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<span>The maximum oxygen uptake is known as the VO max.</span>
Answer:
3924 N
5124 N
4004 N
2884 N
4004 N
Explanation:
m = Mass of elevator = 400 kg
g = Acceleration due to gravity = 9.81 m/s²
a = Acceleration
f = Friction force = 80 N
When the elevator is stationary only the acceleration due to gravity will be acting on it
Tension
The tension is 3924 N
The balanced force equation would be
The tension is 5124 N
When velocity is constant acceleration is zero
The tension is 4004 N
The tension would be 2884 N
When velocity is constant acceleration is zero
The tension is 4004 N