Answer:
205.88 ×mass of rock
This problem uses the expression for the kinetic energy of a moving body. K.E = 1/2mv², where m = mass of rock and v = velocity of the rock.
Explanation:
We are requested to calculate the kinetic energy but in order to do sk we must first calculate the initial velocity at which the rock was thrown downwards.
Given the following: h = -7m (thrown downwards and assuming upwards to be positive), v = -23.43 (same reason) and g = 9.8m/s².
The full calculation can be found in the attachment below.
Answer:
The value is
Explanation:
From the question we are told that
The velocity is [/tex]
The time taken is
The time taken for contact is
The velocity of the of the car after contact is [/tex]
From the equation of kinematics we have that
Here u = 0 \ m/s since the car is initially motionless
=>
=>
Answer:
part (a) v = 1.7 m/s towards right direction
part (b) Not an elastic collision
part (c) F = -228.6 N towards left.
Explanation:
Given,
Part (a)
Pucks are stick together after the collision, therefore the final velocities of the pucks are same as v.
From the conservation of linear momentum,
Direction of the velocity is towards right due to positive velocity.
part (b)
Given,
Final velocity of the second puck =
Let be the final velocity of first puck after the collision.
From the conservation of linear momentum,
For elastic collision, the coefficient of restitution should be 1.
From the equation of the restitution,
Therefore the collision is not elastic collision.
part (c)
Given,
Time of impact = t =
we know that the impulse on an object due to a force is equal to the change in momentum of the object due to the collision,
Negative sign indicates that the force is towards in the left side of the movement of the first puck.
