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muminat
3 years ago
9

Suppose that instead of dropping the rock you throw it downwards so that its speed after falling 7 meters is 23.43 m/s. How much

kinetic energy did you give the rock in your throw

Physics
2 answers:
Mkey [24]3 years ago
8 0

Answer:

205.88 ×mass of rock

This problem uses the expression for the kinetic energy of a moving body. K.E = 1/2mv², where m = mass of rock and v = velocity of the rock.

Explanation:

We are requested to calculate the kinetic energy but in order to do sk we must first calculate the initial velocity at which the rock was thrown downwards.

Given the following: h = -7m (thrown downwards and assuming upwards to be positive), v = -23.43 (same reason) and g = 9.8m/s².

The full calculation can be found in the attachment below.

Shkiper50 [21]3 years ago
5 0

Answer:

3,298.1 Hz

Explanation:

Solution is attached

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Balance the following equations: CUCO3+H2SO4- CUSO4+H2O+CO2​
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3 years ago
A car moving in a straight line starts at X=0 at t=0. It passesthe point x=25.0 m with a speed of 11.0 m/s at t=3.0 s. It passes
Agata [3.3K]

Answer:

Average velocity v = 21.18 m/s

Average acceleration a = 2 m/s^2

Explanation:

Average speed equals the total distance travelled divided by the total time taken.

Average speed v = ∆x/∆t = (x2-x1)/(t2-t1)

Average acceleration equals the change in velocity divided by change in time.

Average acceleration a = ∆v/∆t = (v2-v1)/(t2-t1)

Where;

v1 and v2 are velocities at time t1 and t2 respectively.

And x1 and x2 are positions at time t1 and t2 respectively.

Given;

t1 = 3.0s

t2 = 20.0s

v1 = 11 m/s

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x1 = 25 m

x2 = 385 m

Substituting the values;

Average speed v = ∆x/∆t = (x2-x1)/(t2-t1)

v = (385-25)/(20-3)

v = 21.18 m/s

Average acceleration a = ∆v/∆t = (v2-v1)/(t2-t1)

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3 years ago
Two carts undergo an inelastic collision where they stick together. Cart A has an initial velocity v0, and the second cart B is
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Given 1/2 mA v0²  / mA²vo²  / 2( mA +mB) = 6

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