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andrey2020 [161]
3 years ago
6

="13 - 4 \times 5 \div 2 + 10 = \\ " alt="13 - 4 \times 5 \div 2 + 10 = \\ " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
const2013 [10]3 years ago
3 0

Answer:

So, 13 - 20 ÷2 + 10 = 13 - 10 + 10 = 3 + 10 = 13 ;

Step-by-step explanation:


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Help pleaseeeee!!!!! i stg if no one answers correctly im gonna have another mental breakdown
Afina-wow [57]

Answer:

-6x⁶ + 4x⁴ - 3x³ + 4x² + 12

Step-by-step explanation:

To write an equation in standard form, you want to arrange the terms from increasing to decreasing powers/exponents.

given: 4x² - 6x⁶ + 2x³ + 12 - 5x³+ 4x⁴

First, lets arrange like terms together. Put the terms with the same exponent together.

2x³ - 5x³ + 4x² - 6x⁶ + 12 + 4x⁴

Now combine the terms with the same exponent by subtracting 5x³ from 2x³.

-3x³ + 4x² - 6x⁶ + 12 + 4x⁴

Now let's arrange the terms from increasing to decreasing powers/exponents.

-6x⁶ + 4x⁴ - 3x³ + 4x² + 12

This is your equation in standard form.

Hope this helps!

3 0
3 years ago
Erin has n books. She sold half of her books and then bought 16 more. Which expression represents the number of books Erin has?
Margarita [4]

Answer:

n÷2+16

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Suppose a tank contains 400 gallons of salt water. If pure water flows into the tank at the rate of 7 gallons per minute and the
Strike441 [17]

Answer:

Step-by-step explanation:

This is a differential equation problem most easily solved with an exponential decay equation of the form

y=Ce^{kt}. We know that the initial amount of salt in the tank is 28 pounds, so

C = 28. Now we just need to find k.

The concentration of salt changes as the pure water flows in and the salt water flows out. So the change in concentration, where y is the concentration of salt in the tank, is \frac{dy}{dt}. Thus, the change in the concentration of salt is found in

\frac{dy}{dt}= inflow of salt - outflow of salt

Pure water, what is flowing into the tank, has no salt in it at all; and since we don't know how much salt is leaving (our unknown, basically), the outflow at 3 gal/min is 3 times the amount of salt leaving out of the 400 gallons of salt water at time t:

3(\frac{y}{400})

Therefore,

\frac{dy}{dt}=0-3(\frac{y}{400}) or just

\frac{dy}{dt}=-\frac{3y}{400} and in terms of time,

-\frac{3t}{400}

Thus, our equation is

y=28e^{-\frac{3t}{400} and filling in 16 for the number of minutes in t:

y = 24.834 pounds of salt

6 0
3 years ago
Need help ASAP ,<br><br> -40 points
user100 [1]

Answer:

A

Step-by-step explanation:

MK and KM are the same line segment

and JKM and LMK share two angles K and M as well as the side of MK or KM making it a Side.Angle.Side

5 0
2 years ago
Write three different sentences that could describe the relationship between the quantities $27, $81
Olenka [21]
1) 27+x=81
2)27+81=108
3)81-x=27
8 0
3 years ago
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