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Furkat [3]
3 years ago
7

What is the ion #for lodine (l)?

Chemistry
1 answer:
AveGali [126]3 years ago
5 0

Answer:An iodide ion is the ion I−. Compounds with iodine in formal oxidation state −1 are called iodides. This page is for the iodide ion and its salts, not organo iodine compounds. In everyday life, iodide is most commonly encountered as a component of iodized salt, which many governments mandate.

brainliest pls

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If you heat the cup of soup in the microwave to make it boil. Will it have a higher total kinetic energy than the bowl of soup?
Paha777 [63]

No, The kinetic energy depends upon the number of particles motion. The hot bowl of soup will have greater number of particles in motion and it will contain more kinetic energy than the cup of soup.

8 0
3 years ago
1 what do you understand by the term isotopes 2 why do I should talk of an element process identical chemical properties 3 name
Bad White [126]

Answer:

Isotopes of an element have same number of protons but different number of neutrons. Which means isotopes of an element have same atomic number but different mass number.

The chemical property of an element is determined by the number of electrons. And as all the isotopes have same number of electrons, they have same chemical properties.

Thus as isotopes of an element have same atomic number , they have same number of electrons and protons. As they have different mass number, the number of neutrons will be different. Hydrogen has three isotopes , ^1_1\textrm{H}, ^2_1\textrm{H} and ^3_1\textrm{H}. Thus ^1_1\textrm{H} has no neutron.

5 0
3 years ago
How is oxide different from a neutral oxygen atom
Zepler [3.9K]

Answer: The main difference between oxide and oxygen is that oxide is a chemical compound with at least one oxygen atom while oxygen is an element whose atomic number is 8.

Explanation: let me know if it was right or wrong

4 0
3 years ago
A dilute solution of bromine in carbon tetrachloride behaves as an ideal-dilute solution. The vapour pressure of pure CCl4 is 33
ANEK [815]

Explanation:

The given data is as follows.

     Vapour pressure of pure CCl_{4} = 33.85 Torr

         Temperature = 298 K

      Mole fraction of Br_{2} = 122.36 torr

Therefore, calculate the vapor pressure of Br_{2} as follows.      

     Vapour pressure of Br_{2} = mole fraction of Br_{2} x K of Br_{2}

                                    = 0.050 x 122.36 Torr

                                   = 6.118 Torr

So, vapor pressure of Br_{2} is 6.118 Torr .

Now, calculate the vapor pressure of carbon tetrachloride as follows.

     Vapour pressure of CCl_{4} = mole fraction of CCl_{4} x Pressure of CCl_{4}

                                     = (1 - 0.050) × 33.85 Torr

                                     = 32.1575 Torr

So, vapor pressure of CCl_{4} is 32.1575 Torr  .

Hence, the total pressure will be as follows.

                         = 6.118 Torr + 32.1575 Torr

                         = 38.2755 Torr

Therefore, composition of CCl_{4} = \frac{32.1575 Torr}{38.2755 Torr}

                         = 0.8405

Composition of CCl_{4} is 0.8405 .

And, composition of Br_{2} = \frac{6.118 Torr}{38.2755 Torr}

                                                  = 0.1598

Composition of Br_{2} is 0.1598 .

6 0
3 years ago
The equilibrium of 2H 2 O(g) 2H 2 (g) + O 2 (g) at 2,000 K has a Keq value of 5.31 x 10-10. What is the Keq expression for this
nevsk [136]

Answer:

5.31*10^{-10} = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}

Explanation:

For a chemical reaction, equilibrium is a state at which the rate of the forward reaction equals that of the reverse reaction. The equilibrium constant Keq is a parameter characteristic of this state which is expressed as a ratio of the concentration of the products to that of the reactants.

For a hypothetical reaction:

xA + yB ⇄ zC

The equilibrium constant is :

Keq = \frac{[A]^{x}[B]^{y}}{[C]^{z} }

The given reaction involves the decomposition of H2O into H2 and O2

2H_{2}O\rightleftharpoons 2H_{2} + O_{2}

The equilibrium constant is expressed as :

Keq = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}

Since Keq = 5.31*10^-10

5.31*10^{-10} = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}

3 0
3 years ago
Read 2 more answers
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