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2 years ago

Solve for this please show work tysm

Mathematics

1 answer:

dalvyx [7]2 years ago

8 0

Answer:

P1= -2/3

P2= -10/3

Step-by-step explanation:

take the sq rt of both sides and use both + and - roots

3P+6=4

3P+6=-4

subtract 6 from both sides for each one

3P=-2

P=-2/3

3P=-10

P= -10/3

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An exponential random variable has a standard deviation of 16. Calculate The probability that it takes on a value < 11. Use 3

antiseptic1488 [7]

Answer:

$P(X$

And using the cdf we got:

$P(X$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}, x>0$

And 0 for other case. Let X the random variable that represent the random variable of interest and we know that the distribution is given by:

$X \sim Exp(\lambda)$

We know the variance on this case given by :

$Var(X) = \frac{1}{\lambda^2}$

So then the deviation is given by:

$Sd(X) = \frac{1}{\sqrt{\lambda}}$

And if we solve for $\lambda$ we got:

$\lambda = (\frac{1}{16})^2 = \frac{1}{256}$

The cumulative distribution function for the exponential distribution is given by:

$F(x) = 1- e^{-\lambda x}$

Solution to the problem

And for this case we want to find this probability:

$P(X$

And using the cdf we got:

$P(X$

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3 years ago

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