Question

A solution contains only sucrose and water. If the mole fraction of sucrose is 0.0558, determine the molality of sucrose.

Answer 1

Answer:

The correct solution is "3.28 m".

Explanation:

According to the question,

Mol fraction of solvent,

= 0.0558

Molar mass of water,

= 18 g/mol

Mol of H₂O in 1000 g water,

= 55.55 mol

Now,

Let the mol of solute will be "x mol".

Total mol in solution will be "55.55 + x".

As we know,

⇒ The mol fraction of solvent = $\frac{x}{55.55+x}$

                                        $0.0558=\frac{x}{55.55+x}$

                                                $x=0.0558[55.55+x]$

                                                $x=3.09969+0.0558x$

                               $x-0.0558x=3.09969$

                                               $x=\frac{3.09969}{0.9442}$

                                                  $=3.38 \ m$