Answer:
To regulate the gas pressure in the lighter tank and avoid build-up of pressure.
Explanation:
- First, you need to understand the properties of this organic molecule. Butane. C₄H₁₀ is a colorless, odorless, but HIGHLY FLAMMABLE liquefied gas. The liquid is flammable at 25⁰C whilst the vapor is flammable at 15⁰C. As you can see, this is an extremely flammable gas. It has a high vapor pressure (tendency by liquids to escape as gas molecules)
- Any external heat source induces a pressure build up that might cause the gas to explode when there is an open flame.
- Combining the two points above, a thermo-regulated water bath that has a lower temperature (below 15⁰C) will be need to prevent the pressure build up and ensure that any leakage will not have a high vapor pressure.
Answer:
E) Silver, mass = 420 g, d = 10.5 g/cm.
Explanation:
Hello,
In this case, since the density is defined by:

Given the mass and density, we compute the volume via:

Thus, for each vase we have:
A) 
B) 
C) 
D) 
E) 
In such a way, the largest volume corresponds to E) Silver, mass = 420 g, d = 10.5 g/cm.
Best regards.
The volume of O₂ produced: 84.6 L
<h3>Further explanation</h3>
Given
7.93 mol of dinitrogen pentoxide
T = 48 + 273 = 321 K
P = 125 kPa = 1,23365 atm
Required
Volume of O₂
Solution
Decomposition reaction of dinitrogen pentoxide
2N₂O₅(g)→4NO₂(g)+O₂ (g)
From the equation, mol ratio N₂O₅ : O₂ = 2 : 1, so mol O₂ :
= 0.5 x mol N₂O₅
= 0.5 x 7.93
= 3.965 moles
The volume of O₂ :

Answer:
you would find it in section 3 as these are semi-metals
Explanation:
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