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Vedmedyk [2.9K]
3 years ago
11

Calculate the change in length of a 90.5 mm aluminum bar that has increased in temperature by from -14.4 oC to 154.6 oC

Physics
1 answer:
nignag [31]3 years ago
5 0

Answer:

 ΔL = 3.82 10⁻⁴ m

Explanation:

This is a thermal expansion exercise

          ΔL = α L₀ ΔT

          ΔT = T_f - T₀

where ΔL is the change in length and ΔT is the change in temperature

Let's reduce the length to SI units

          L₀ = 90.5 mm (1m / 1000 mm) = 0.0905 m

let's calculate

          ΔL = 25.10⁻⁶ 0.0905 (154.6 - (14.4))

          ΔL = 3.8236 10⁻⁴ m

     

using the criterion of three significant figures

          ΔL = 3.82 10⁻⁴ m

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Answer:

p to the left

Explanation:

According to law of conservation of momentum "total momentum of an isolated system remains constant".

we consider astronaut and astronaut drill as an isolated system. If the drill gain momentum p to the right so in order for momentum to remain constant the astronaut will gain the same momentum but in opposite direction i.e momentum p to the left.

Initial momentum = 0 ( before she throw astronaut belt)

Final momentum = p - p = 0 (After she throw astronaut belt)

Hence momentum of the system remains constant i.e zero.

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3 years ago
An object is moving east with a constant speed of 30 m/s for 5 seconds. What is the object’s acceleration?
Shtirlitz [24]

Answer:

6 m/s²

Explanation:

From the question given above, the following data were obtained:

Velocity (v) = 30 m/s

Time (t) = 5 s

Acceleration (a) =..?

Acceleration is defined mathematically as:

Acceleration (a) = Velocity (v) /time (t)

a = v /t

With the above formula, we can obtain the acceleration of the object as follow:

Velocity (v) = 30 m/s

Time (t) = 5 s

Acceleration (a) =..?

a= v/t

a= 30/5

a = 6 m/s²

Therefore, the acceleration of the object is 6 m/s² due East.

7 0
3 years ago
Consider a collection of charges in a given region and suppose all other charges are distant and have a negligible effect. Furth
AlladinOne [14]

Answer:

E. Some charges in the region are positive, and some are negative.

Explanation:

Electric potential is given as;

V = \frac{W}{Q}

where;

W is the work done in moving a charge between two points which have a difference in potential

Q is quantity of charge in the given region

If the electric potential at a given point in the region is zero, then sum of the charges in the given region must be equal to zero. For the charges to sum to zero, some will be positive while some will be negative,.

Therefore, the correct statement in the given options is "E"

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3 years ago
Which of the following elements most likely has the highest boiling point?
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Answer:

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4 0
3 years ago
Read 2 more answers
In a certain chemical process, a lab technician supplies 292 J of heat to a system. At the same time, 68.0 J of work are done on
vekshin1

Answer:

The increase in the internal energy of the system is 360 Joules.

Explanation:

Given that,

Heat supplied to a system, Q = 292 J

Work done on the system by its surroundings, W = 68 J

We need to find the increase in the internal energy of the system. It can be given by first law of thermodynamics. It is given by :

dE=dQ+dW\\\\dE=292\ J+68\ J\\\\dE=360\ J

So, the increase in the internal energy of the system is 360 Joules. Hence, this is the required solution.

3 0
3 years ago
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