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2 years ago

Scientific laws explain_____.

Physics

2 answers:

saveliy_v [14]2 years ago

8 0

A pattern in nature observed over and over

GREYUIT [131]2 years ago

6 0

Answer: a pattern in nature observed over and over

Explanation:

A scientific law can be define as statement which either describes or predict the natural phenomena. The information given in the scientific law is verified by the experimental procedures and observations which are done under conditions which are tried to mimic the natural system. It can be used to describe the cause of a natural phenomena, duration of natural phenomena and conditions necessary for the occurrence of natural phenomena and also gives information why and how a natural phenomena repeat itself.

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Manipulate the equation "v=d/t" to find the answers to these problems using

OLEGan [10]

Yo no me voy a ir a la cama a

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2 years ago

What is the gravitational potential energy of a 0.550-kg projectile flying with 335 m/s, 72 meters above the ground?

Fofino [41]

Answer:

GPE = 388.08 Joules.

Explanation:

Given the following data;

Mass = 0.550kg

Speed = 335 m/s

Height = 72 meters

We know that acceleration due to gravity, g is equal to 9.8 m/s²

To find the gravitational potential energy;

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

$G.P.E = mgh$

Where;

G.P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Substituting into the formula, we have;

$G.P.E = 0.550 * 9.8 * 72$

GPE = 388.08 Joules.

4 0

2 years ago

An automobile with passengers has weight 19.4 kN and is moving at 108 km/h when the driver brakes to a stop. The frictional forc

mixer [17]

Answer:

12.0

Explanation:

4 0

2 years ago

A 62 kg skier is moving at 6.5 m/s on frictionless horizontal snow-covered plateau when she encounters a rough patch 3.50 m long

Degger [83]

Answer:

(A). The work done by friction in crossing the patch is -637.98 J.

(B). The speed of skier is 10.57 m/s.

Explanation:

Given that,

Mass of skier = 62 kg

Speed = 6.5 m/s

Length = 3.50 m

Coefficient kinetic friction = 0.30

Height = 2.5 m

(A) we need to calculate the work done by friction in crossing the patch

Using formula of work done

$W=-\mu mg\times l$

Put the value into the formula

$W=-0.30\times62\times9.8\times3.50$

$W=-637.98\ J$

The work done by friction in crossing the patch is -637.98 J.

(B) we need to calculate the speed of skier

Using conservation of energy

$K.E_{i}+U_{i}-W_{friction}=K.E_{f}+U_{f}$

$\dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2+U_{f}$

Final potential energy is zero

So, $\dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2$

$\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}v_{1}^2+gh-\mu gl$

Put the value into the formula

$\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}\times6.5^2+9.8\times2.5+0.30\times9.8\times3.50$

$v_{2}=\sqrt{2\times55.915}$

$v_{2}=10.57\ m/s$

The speed of skier is 10.57 m/s.

Hence, (A).The work done by friction in crossing the patch is -637.98 J.

(B).The speed of skier is 10.57 m/s.

6 0

2 years ago

a car starts from the rest and accelerates at 9.54m/s for 6.5 seconds. what is the distance covered by the car

uysha [10]

Answer:

= 201.53 meters

Explanation:

A car started from rest and accelerated at 9.54 m/s^2 for 6.5 seconds. How much distance was covered by the car?

Use the formula d = $\frac{at^{2} }{2} ,$

where d is the distance, t is the time and "a" is the acceleration.
$d=\frac{9*54*6*5^{2} }{2} = 201.53 m$

3 0

1 year ago