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3 years ago

11

Debate right now Saitama versus Goku

2 answers:

Sav [38]3 years ago

5 0

Saitama would most definitely beat goku

Vikki [24]3 years ago

3 0

Answer:

Goku

Explanation:

He's got the kaio-ken speed punches kamehameha!!

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The main source of this energy is <br> .

USPshnik [31]

Answer:motion

Explanation:

kinetic energy of an object that it possess due to its motion.

5 0

2 years ago

Read 2 more answers

I REaLLy NEEd hELP WITh THIs SCIENCE. ASAP!!!!!!!! :D

vivado [14]

Answer:

e&d

Explanation:

7 0

3 years ago

A satellite moves in a circular orbit a distance of 1.6×10^5 m above Earth's surface. (radius of Earth is 6.38 x 10^6m and its m

Rashid [163]

Answer:

The speed of the satellite is 7809.52 m/s

Explanation:

It is given that,

Radius of Earth, $r=6.38\times 10^6\ m$

Mass of earth, $M=5.98\times 10^{24}\ kg$

A satellite moves in a circular orbit a distance of, $d=1.6\times 10^5\ m$ above Earth's surface.

We need to find the speed of the satellite. It is given by :

$v=\sqrt{\dfrac{GM}{R}}$

R = r + d

$R=(6.38\times 10^6\ m+1.6\times 10^5\ m)=6540000\ m$

So, $v=\sqrt{\dfrac{6.67\times 10^{-11}\ Nm^2/kg^2\times 5.98\times 10^{24}\ kg}{6540000\ m}}$

v = 7809.52 m/s

So, the speed of the satellite is 7809.52 m/s. Hence, this is the required solution.

5 0

3 years ago

In a transverse wave, the motion of the disturbance is in what direction relative to the wave motion? opposite parallel perpendi

Vikentia [17]

Answer:

$\displaystyle Perpendicular$

Explanation:

<em>Longitudinal</em><em> </em><em>waves</em><em> </em>are parallel to the direction of the motion of the disturbance, while <em>transverse</em><em> </em><em>waves</em><em> </em>are perpendicular to the direction of the motion of the disturbance.

I am joyous to assist you anytime.

8 0

4 years ago

Read 2 more answers

An electric field of intensity 3.25 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.

jekas [21]

Answer:

$\varphi_1= 796.25 N m^2/C$

$\varphi_2= 0 N m^2/C$

$\varphi_3=686.1 N m^2/C$

Explanation:

From the question we are told that

Electric field of intensity $E= 3.25 kN/C$

Rectangle parameter Width $W=0.350 m$ Length $L=0.700 m$

Angle to the normal $\angle=30.5 \textdegree$

Generally the equation for Electric flux at parallel to the yz plane $\varphi_1$ is mathematically given by

$\varphi_1=EA cos theta$

$\varphi_1=3.25* 10^3 N/C * ( 0.350)(0.700) cos 0$

$\varphi_1= 796.25 N m^2/C$

Generally the equation for Electric flux at parallel to xy plane $\varphi_2$ is mathematically given by

$\varphi_2=EA cos theta$

$\varphi_2=3.25* 10^3 N/C * ( 0.350)(0.700) cos 90$

$\varphi_2= 0 N m^2/C$

Generally the equation for Electric flux at angle 30 to x plane $\varphi_3$ is mathematically given by

$\varphi_3=EA cos theta$

$\varphi_3=3.25* 10^3 N/C * ( 0.350)(0.700) cos 30.5$

$\varphi_3=686.072219 N m^2/C$

$\varphi_3=686.1 N m^2/C$

7 0

3 years ago