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2 years ago

How is energy harnessed to do useful work?

Physics

1 answer:

baherus [9]2 years ago

8 0

Answer:

But there are ways to harness kinetic energy to either generate useful mechanical work or electricity. This is what many have tried to do to make use of energy that would be otherwise wasted. One way to harness kinetic energy that has popped up many times in recent years has to do with roads and speed bumps

Explanation:

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How are all paths that have a displacement of zero similar?

igomit [66]

<span>Displacement is identified as the net movement of a thing with detail to its initial location. One may journey out of his city and come back. Notwithstanding having enclosed many miles, he will have a displacement of 0. This is true for all trails that have zero displacement that they all go back to their initial position.</span>

8 0

2 years ago

Read 2 more answers

A gaseous refrigerant undergoes compression when 150 j of work is done on it. if the internal energy of the gas increases by 120

zhenek [66]

The heat transferred is -30J

When the gas undergoes compression, work is done on the gas and its internal energy increases.

According to the first law of thermodynamics, the increase in internal energyΔU is the sum of the heat given to the gas ΔQ and the amount of work done on the gas ΔW

$\Delta U=\Delta Q +\Delta W$

The work done on the gas is 150 J due to compression and the internal energy of the gas increases by 120 J.

Therefore, the heat given to the gas is given by,

$\Delta Q =\Delta U -\Delta W\\ =120 J -150 J\\ =-30 J$

Thus, an amount of heat equal to 30 J flows out of the system.

3 0

3 years ago

A coil has N turns enclosing an area of A. In a physics laboratory experiment, the coil is rotated during the time interval Δt f

scoray [572]

Answer:

$\dfrac{NBA}{\Delta t}$

Explanation:

B = Magnetic field

A = Area

$\theta$ = Angle

t = Time taken

Before rotation the magnetic flux is given by

$\phi_i=BAsin\theta\\\Rightarrow \phi_i=BAsin90\\\Rightarrow \phi_i=BA$

Magnetic flux is BA

After rotation the magnetic flux is given by

$\phi_i=BAsin\theta\\\Rightarrow \phi_i=BAsin0\\\Rightarrow \phi_i=0$

The magnetic flux is 0

Magnitude of emf is given by

$\epsilon=NA\dfrac{d\phi}{dt}\\\Rightarrow \epsilon=\dfrac{NBA}{\Delta t}$

The magnitude of the average emf induced in the entire coil is $\dfrac{NBA}{\Delta t}$

4 0

2 years ago

I NEED HELP, PLEASE.

Zinaida [17]

Hello,

I'd be glad to help.

Momentum = (mass) times (speed)

= (75 kg) x (18 m/s)

= 1,350 kg-m/s .

Hope this helps

5 0

2 years ago

2. Fracture mechanics. A structural component in the form of a wide plate is to be fabricated from a steel alloy that has a plan

ikadub [295]

Answer:

the critical flaw is subject to detection since this value of ac (16.8 mm) is greater than the 3.0 mm resolution limit.

Explanation:

This problem asks that we determine whether or not a critical flaw in a wide plate is subject to detection given the limit of the flaw detection apparatus (3.0 mm), the value of KIc (98.9 MPa m), the design stress (sy/2 in which s y = 860 MPa), and Y = 1.0.

$ac=1/\pi (\frac{Klc}{Ys} )^{2}\\ ac=1/\pi(\frac{98.9}{(1)(860/2)} )^{2}\\ ac=0.0168m\\ac=16.8mm$

Therefore, the critical flaw is subject to detection since this value of ac (16.8 mm) is greater than the 3.0 mm resolution limit.

5 0

3 years ago