Look at!!:
Pre image A(3,4), B(1,5) C(6,6);
If you multiply these coordinates by 3/2, you get its images:
A(3,4) ⇒ A`(3*3/2, 4*3/2)=(4.5, 6)
B(1,5) ⇒B`(1.*3/2, 5*3/2)=(1.5, 7.5)
C(6,6) ⇒C`(6*3/2, 6*3/2)=(9,9)
Therefore the scale factor is 3/2.
When the scale factor of a dilation is >1, then we have an enlargement, an expansion.
In this case 3/2=1.5>1
Answer:
The dilation is expansion.
The scale factor is 3/2.
Answer:
Step-by-step explanation:
the transverse axis is horizontal.
so its a horizontal hyperbola
Center is the origin so center is (0,0)
Equation of horizontal hyperbola is
Given a= 55000 and c= 81000
c^2 = a^2 + b^2
81000^2 = 55000^2 + b^2
subtract 55000^2 on both sides
b = sqrt(81000^2 - 55000^2)= 59464.27
now plug in the values
Answer:
0.1587
Step-by-step explanation:
Given the following :
Mean (m) of distribution = 64 inches
Standard deviation (sd) of distribution = 2 inches
Probability that a randomly selected woman is taller than 66 inches
For a normal distribution :
Z - score = (x - mean) / standard deviation
Where x = 66
P(X > 66) = P( Z > (66 - 64) / 2)
P(X > 66) = P(Z > (2 /2)
P(X > 66) = P(Z > 1)
P(Z > 1) = 1 - P(Z ≤ 1)
P(Z ≤ 1) = 0.8413 ( from z distribution table)
1 - P(Z ≤ 1) = 1 - 0.8413
= 0.1587
Answer:
36 pencils
Step-by-step explanation:
Let h and p represent the number of highlighters and the number of pencils, respectively.
Then h + p = 45, and h = 45 - p.
Tom paid a total of $30 for these supplies, with ($2/highligher)(h) + ($0.333/pencil) adding up to that amount.
substituting 45 - p for h in 2h + 0.333p = 30, we get:
2(45 - p) + 0.333p = 30, or
90 - 2p + 0.333p = 30
Combine the constants: 60 = 2p - 0.333p, or 60 = 1.667p
Then p = 60/1.667 = 35.9928, or 36.
Tom bought 36 pencils for $12, and 45-36, or 9, highlighters for $18, for a total purchase of $30. This shows that these calculations are correct.
