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jolli1 [7]
3 years ago
13

Belinda is thinking about buying a car for $38,000. The table below shows the projected value of two different cars for three ye

ars:
Number of years 1 2 3
Car 1 (value in dollars) 32,000 26,000 20,000
Car 2 (value in dollars) 32,300 27,455 23,336.75


Part A: What type of function, linear or exponential, can be used to describe the value of each of the cars after a fixed number of years? Explain your answer. (2 points)
Part B: Write one function for each car to describe the value of the car f(x), in dollars, after x years. (4 points)
Part C: Belinda wants to purchase a car that would have the greatest value in five years. Will there be any significant difference in the value of either car after five years? Explain your answer, and show the value of each car after five

Please be serious
Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
3 0

Answer:

108.01

Step-by-step explanation:

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The probability that a lab specimen contains high levels of contamination is 0.15. A group of 4 independent samples are checked.
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Simplify (Are all division)<br><br>2+4i<br>3i<br><br>3+2i<br>4+i<br><br>2i^11
Alla [95]

We\ know:\ i=\sqrt{-1}\to i^2=-1

\dfrac{2+4i}{3i}=\dfrac{2+4i}{3i}\cdot\dfrac{3i}{3i}=\dfrac{6i+12i^2}{9i^2}=\dfrac{6i+12(-1)}{9(-1)}\\\\=\dfrac{6i-12}{-9}=\dfrac{2i-4}{-3}=\dfrac{4}{3}-\dfrac{2}{3}i

\dfrac{3+2i}{4+i}=\dfrac{3+2i}{4+i}\cdot\dfrac{4-i}{4-i}=\dfrac{(3+2i)(4-i)}{4^2-i^2}\\\\=\dfrac{(3)(4)+(3)(-i)+(2i)(4)+(2i)(-i)}{16-(-1)}=\dfrac{12-3i+8i-2i^2}{16+1}\\\\=\dfrac{12+5i-2(-1)}{17}=\dfrac{12+5i+2}{17}=\dfrac{14+5i}{17}=\dfrac{14}{17}+\dfrac{5}{17}i

2i^{11}=2i^{10+1}=2i^{10}i^1=2i^{2\cdot5}i=2i(i^2)^5=2i(-1)^5=2i(-1)=-2i


Used:\ (a+b)(a-b)=a^2-b^2

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