The perimeter p of the rectangle with length l and width w is:
p = 2l + 2w
that is, two times its length and two times its width, lets solve for the width w and substitute known data:
<span>p = 2l + 2w
</span>2w = p - 2l
w = (<span>p - 2l</span>)/2
w = (56 - (2*12))/2
w = (56 - 24)/2
w = 32/2
w = 16
therefore the width of the rectangle is 16 in
Answer:
D
Step-by-step explanation:

Answer:
19 nails
Step-by-step explanation:
Let's first determine the z-score by using the formula:

Where x=5.03, μ=5, σ=0.03 and so:

We can now use a z-score table to determine that 1.00 is synonymous with 0.8413 meaning 84.13%. This means that 84.13% of the nails are less than or equal to 5.03 inches long. Therefore, since we know 100% = 1 in decimals we can determine that the length greater than 5.03 inches is 1-0.8413=0.1587. This means that 15.87% of the 120 nails are greater than 5.03 inches long.
Finally, we can determine how many nails are greater than 5.03 by determining what is 15.87% of 120 which is:

And so 19 out of the 120 nails are greater than 5.03 inches long.
Answer:
C
Step-by-step explanation:
-8 14 = 42 (He subtracted 14 from 42)
-8p = 28 (Which is how he got 28)
p = -3.5 (He took 28 divide by -8 which got him -3.5)