Q1
I like to use the standard form to write the equation of a perpendicular line, especially when the original equation is in that form. The perpendicular line will have the x- and y-coefficients swapped and one negated (remember this for Question 3). Thus, it will be
... 5x - 2y = 5(6) - 2(16) = -2
Solving for y (to get slope-intercept form), we find
... y = (5/2)x + 1 . . . . . matches selection C
Q2
The given equation has slope -3/6 = -1/2, so that will be the slope of the parallel line. (matches selection A)
Q3
See Q1 for an explanation. The appropriate choice is ...
... B. 4x - 3y = 5
Q4
The given line has slope -2, so you can eliminate all choices except ...
... D. -2x
Q5
The two lines have the same slope (3), but different intercepts, so they are ...
... A. parallel
Answer:
D
Step-by-step explanation:
Given the quadratic
d = - 16t² + 12t ← subtract d from both sides
- 16t² + 12t - d = 0 ← in standard form
with a = - 16, b = 12, c = - d
Use the quadratic formula to solve for t
t = ( - 12 ± 
) / - 32
= ( - 12 ± 
) / - 32
= ( - 12 ± 
) / - 32
= ( - 12 ± 4
) / - 32
= 
± 
= 
± 
= ± 
→ D
Answer:
x = 10
Step-by-step explanation:
Step 1: Write equation
3x - 8 = 22
Step 2: Add 8 to both sides
3x = 30
Step 3: Divide both sides by 3
x = 10
Answer:
Step-by-step explanation:
They both (36 and 45) go into 9. Divide them both by 9.
