Answer:
As we know:
A nickle is worth 5 cents.
A dime is worth 10 cents.
A quarter is worth 25 cents.
Here is what Robert had:
Number of nickles (a)
Number of dimes (b)
Number of quarters (c)
Here is assumption:
5a + 10b + 25c = 850
a = 3b
c = b + 10
=> 5(3b) + 10b + 25(b + 10) = 850
=> 50b + 250 = 850
=> 50b = 600
=> b = 600/50 = 12
=> a = 3b = 3 x 12 = 36
=> c = b + 10 = 12 + 10 = 22
=> Number of nickles: 36
=> Number of dimes: 12
=> Number of quarters: 22
Hope this helps!
:)
Answer: 1/4
Step-by-step explanation:
Answer:
3(2x^2-3x+14)
Step-by-step explanation:
6x^2-9x+42
All three terms have a common factor of 3
3(2x^2-3x+14)
Now let's focus on 2x^2-3x+14 and bring down the factor 3 later
so a=2
b=-3
c=14
Let's try to find two factors for ac that multiply to be a*c and add up to be b.
ac=28
b=-3
-----
ac=7(4)=14(2)=8(2)
Even if I made these pairs with both negatives nothing would give me -3
So you can only go as far as 3(2x^2-3x+14)
Here is another thing to help you if you have ax^2+bx+c and b^2-4ac<0 then it can't be factored (over reals)
4+.95=4.95
4.95*3= 14.85
The student paid $14.85 for the three cans.
