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Fiesta28 [93]
3 years ago
11

During a qualitative analysis experiment a student found his unknown salt to contain mn2 and po43- ions. write the chemical form

ula for their unknown salt. do not include phases with your answer.

Chemistry
1 answer:
MrMuchimi3 years ago
3 0

The ions in the unknown salt are:

Mn^{2+} and PO_{4}^{3-}

The chemical formula of the salt is determined as shown in the picture.

The chemical formula of the salt is Mn_3(PO_{4})_{2}.


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Answer:

Explanation:

2. a [CO3 2-][H3O+] / [H2O][HCO3-

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5 0
3 years ago
Which of the following describes a property of water that helps sustain marine life forms?
Mariana [72]

Answer:

Open spaces in water's solid structure makes its solid state less dense than its liquid state.

Explanation:

  • Water unlike other liquids is special. It contracts when cooled, down to a temperature of 4°C but thereafter begins to expand as it reaches 0°C and turns into ice.
  • This property is useful for the preservation of marine life in very cold temperatures. During winter, the surface water in water lakes and rivers starts cooling. Upon reaching the temperature of 4°C, the surface water descends to the bottom as it denser.
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4 0
3 years ago
Calculate the molarity of H3PO4 when you added 57.3 g into 3,820 mL of water
motikmotik

Answer:

0.153M

Explanation:

57.3/97.994 (molar mass)=0.585 moles of H3PO4

.0585/3.820L=0.153M

5 0
3 years ago
What is the mass of 8.12 × 10^23 molecules of CO2 gas? (Atomic mass of carbon = 12.011 u; oxygen = 15.999 u.)
amid [387]

Answer:

m=59.3gCO_2

Explanation:

Hello,

In this case, the first step is to compute the molar mass of carbon dioxide as shown below, considering it has one carbon atom and two oxygen atoms:

M=12.011g/mol+2*15.999g/mol\\\\M=44.009g/mol

It is important to notice it is the mass in one mole of such compound. Afterwards, we need to use the Avogadro's number to compute the how many moles are in the given molecules of carbon dioxide as shown below:

mol=8.12x10^{23}molec*\frac{1mol}{6.022x10^{23}molec} =1.35mol

Finally, the mass by using the molar mass:

m=1.35mol*\frac{44.009g}{1mol} \\\\m=59.3gCO_2

Best regards.

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3 years ago
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5 0
3 years ago
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