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asambeis [7]
2 years ago
8

What volume would a 23.8 g sample of sulfur dioxide take up if it were stored at STP7

Chemistry
1 answer:
IceJOKER [234]2 years ago
4 0

Answer:

Hh

Explanation:

Bb

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The addition of NaOH to water would result in which of the following?
EleoNora [17]

Answer:

A decrease in [H3O+] and an increase in pH (option a)

Explanation:

Equilibrium of water is shown in this equation

2H₂O  ⇄  H₃O⁺  +  OH⁻

When you add NaOH, you are modifying [OH⁻]

NaOH  →   Na⁺  +  OH⁻

In equilibrium of water, the [OH⁻] increases

2H₂O   ⇄   ↓  H₃O⁺   +   OH⁻  ↑

As the [OH⁻] increases, by Le Chatellier, the equilibrium tends to decrease [H₃O⁺].

If the [OH⁻] is higher, pH  is also high so the solution of water and sodium hydroxide would be totally basic.

3 0
3 years ago
2) what is the mass of 6.02 x 1023 atoms of arsenic?
zzz [600]
Data:
Arsenic Molar Mass = 74,9216 ≈ 75 u (<span>atomic mass unit)</span>

Solving:

1 mole of arsenic → 75g ------------ 6,02*10²³ molecules
..................................X -------------- 1 molecule

6,02*10²³X = 75
x = \frac{75}{6,02*10^{23}}
\boxed{x \approx 1,24*10^{24}grams}
6 0
2 years ago
PLEASE HELP WILL GIVE BRAINLIEST!!!!
Anna [14]

Answer:

\boxed{It\ will\ shift\ to\ create\ less\ of\ substance\ A}

Explanation:

If the concentration of any substance A in a dynamic equilibrium increases, The equilibrium will be  shifted to its opposite side so that Substance A can be created less and the substance opposite to A can be created more so that a "dynamic equilibrium" can again be established.

3 0
3 years ago
Consider the following unbalanced reaction: P4(s) + F2(g) → PF3(g) What mass of fluorine gas is needed to produce 120. g of PF3
Studentka2010 [4]

Answer:

44.28 grams.

Explanation:

Let us write the balanced reaction:

P_{4}+6F_{2}-->4PF_{3}

As per balanced equation, six moles of fluorine gas will give four moles of PF₃.

The mass of PF₃ required = 120 g

The molar mass of PF₃ = 88g/mol

Moles of PF₃ required =\frac{mass}{molarmass}=\frac{120}{88}=1.364mol

The moles of fluorine gas required = \frac{4X1.364}{6}=0.91

the mass of fluorine gas required = moles X molar mass = 0.91x38 = 34.58g

Now this much mass will be required if the reaction is of 100% yield

But as given that the yield of reaction is only 78.1%

The mass of fluorine required = \frac{massX100}{78.1} =\frac{34.58X100}{78.1} =44.28g

4 0
3 years ago
All of the following statements about carbohydrates are true EXCEPT: Group of answer choices they are composed of carbon, hydrog
vitfil [10]

Whats the question?                            Cause idk

                             

6 0
2 years ago
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