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lubasha [3.4K]
3 years ago
14

If you fill your car tire to a pressure of 32 psi (pounds per square inch) on a hot summer day when the temperature is 35°C (95°

F), what is the pressure (in psi) on a cold winter day when the temperature is -15°C (5°F)? Assume no gas leaks out between measurements and the volume of the tire does not change.
Chemistry
1 answer:
Murrr4er [49]3 years ago
4 0
By Gay Lussacs law you can find the pressure. First both temperatures of Celsius must change to Kelvin by adding 273. Temperature one will be 308K and temperature 2 will be 258K
With this info, you can now find the pressure with Lussacs law

P1 = P2
— —
T1 T2

Pressure 1 is given which is 32 psi so just plug it all in and find P2

32 = x
—— ——
308 258

308x = 8256 (Cross multiply)

X = 26.8 (divide both sides by 308)

Answer is 26.8 PSI

This makes sense because as temperature increases pressure increases, as well as when temperature decreases, pressure decreases. Since it’s a colder day the pressure will be lower.
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B. What useful functions do oxidation numbers
disa [49]

Explanation:

b. What useful functions do oxidation numbers  serve?

It is used to show oxidation and reduction (loss and gain of electrons)

b. How many molecules are in 1 mole of  molecules?

1 mole = 6.022 * 10^23 molecules

c. What is the name given to the number of  molecules in 1 mole?

Avogadro's Number of molecules

21. a. What is the molar mass of an element?

This is the mass of an element divided by the number of moles.

Molar mass = Mass / Number of moles

b. Write the molar mass rounded to two  decimal places of carbon, neon, iron and  uranium.

amu = Atomic Mass Unit

Carbon = 12.01 amu

Neon = 20.18 amu

Iron = 55.85 amu

Uranium = 238.03 amu

7 0
3 years ago
Why would the volume of one object calculated using “Measurement and Calculation” differ from the volume of the same object calc
Mars2501 [29]

Answer:

Measuring the Volume of Solids

Rectangular prism - Multiply the measurement of the length times the width, then times the height.

Cube - Since all sides are the same measurement, it would be the measurement of any side, or edge, cubed, or a³

Explanation:

8 0
3 years ago
Read 2 more answers
Please help its easy but i don't feel like doing it
KonstantinChe [14]

Answer:

first one is a second one is e

Explanation:

7 0
3 years ago
ASAP help with these please.
german

Answer:

1. See explanation below

2. Density

3. Masses

Explanation:

1. Your picture is a bit too small to see the values but maybe this will help you.

To determine the maximum maximum mass in grams that triple beam balance can measure all you have to do is add up the maximum of each beam. So all you need to do is see the value at the last notch of each beam.

However, if you are referring to the picture that is attached in the bottom: The answer would be 610g. Because the last notches of each beam are as follows:

100 g

500 g

10 g

So we add that we get 610g.

2. density can be computed using the formula:

D = M/V

where:

D = density

M = mass

V = volume

As you can see in the both figures A and B measure 20 g, this means that their masses are the same. The density of objects can be different when either their masses, or their volumes are different. So even if they have the same mass, they can have different densities because they have different volumes.

3. Force of gravitational attraction between two objects is dependent on the masses of the two objects and the distance. The larger the mass, the stronger the gravitational force of attraction. This means that they have a direct relationship. Now when it comes to distance, the further apart they are the weaker the gravitational force of attraction, or in other words, they are indirectly related.

6 0
3 years ago
If the mass of the object below is 28g, what is the density of the object below. Units are in cm below. Please round your answer
Murljashka [212]

Answer:

d = 0.93 g/cm³

Explanation:

Given data:

Mass of object = 28 g

Volume of object = 3cm×2cm×5cm

density of object = ?

Solution:

Volume of object = 3cm × 2cm ×5cm

Volume of object = 30 cm³

Density of object:

d = m/v

by putting values,

d = 28 g/ 30 cm³

d = 0.93 g/cm³

3 0
3 years ago
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