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MAXImum [283]
3 years ago
9

How many moles are in 55.0 g calcium nitrate?

Chemistry
1 answer:
Alex17521 [72]3 years ago
5 0

Answer: 0.335 mols Ca(NO3)2

Explanation: To go from grams to mols you divide grams by the molar mass of the substance so, 55/164.088 = 0.335

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What is the boiling point, melting point, and triple point of bromine?
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Answer:

A. Boiling point = 59 °C, Melting point = -7.2°C, triple point = -7.3°C

Explanation:

3 0
3 years ago
The equilibrium constant, Kp, for the following reaction is 0.497 at 500K.PCl5(g) PCl3(g) + Cl2(g)If an equilibrium mixture of t
Anestetic [448]

<u>Answer:</u> The equilibrium partial pressure of chlorine gas is 0.360 atm

<u>Explanation:</u>

For the given chemical equation:

PCl_5(g)\rightleftharpoons PCl_3(g)+Cl2(g)

The expression of K_p for above reaction follows:

K_p=\frac{p_{Cl_2}\times p_{PCl_3}}{p_{PCl_5}}

We are given:

K_p=0.497\\p_{PCl_3}=0.651atm\\p_{PCl_5}=0.471atm

Putting values in above equation, we get:

0.497=\frac{p_{Cl_2}\times 0.651}{0.471}\\\\p_{Cl_2}=0.360atm

Hence, the equilibrium partial pressure of chlorine gas is 0.360 atm

5 0
3 years ago
2. Fluorine gas exerts a pressure of 1.2 atm. When the
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Answer:

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6 0
2 years ago
A mixture of helium, nitrogen and oxygen has a total pressure of 756 mmHg. The partial
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Answer:

The  partial pressure of oxygen in the mixture is 296 mmHg.

Explanation:

The pressure exerted by a particular gas in a mixture is known as its partial pressure. So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone.

This relationship is due to the assumption that there are no attractive forces between the gases.

So, in this case, the total pressure is:

PT=Phelium + Pnitrogen + Poxygen

You know:

  • PT= 756 mmHg
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Replacing:

756 mmHg= 122 mmHg + 338 mmHg + Poxygen

Solving:

756 mmHg - 122 mmHg - 338 mmHg = Poxygen

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<u><em>The  partial pressure of oxygen in the mixture is 296 mmHg.</em></u>

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3 years ago
Which agency publishes the food code
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4 0
4 years ago
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